Ex Clearly please , use table to solve use tableTableDerive expressions for the heat absorbed by the system for each of the following classes of reversibleprocesses for one mole of an idea gas:(a) Case 1: Isothermal change in pressure(b) Case 2: Isobaric change in volumeHint: Case 1 with S = S(T,P); Case 2 with S = S(P,V)(c) Case 3: Isochoric (constant volume) change in temperaturedV=Va dT-VB APdS=CT dT-Va dPdU= (Cp-PVα) dT + V(PB - Ta) dPdH=Cp dT +V(I-Ta) dPdF=-(S+PVa) dT + VPB dPdG=-S dT + V dP

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Answered: use table Table Derive expressions for…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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One mole of an ideal gas is heated slowly so that it goes from the PV state (P, V;) to (2P;, 2V;) in such a way that the pressure is directly proportional to the volume. (a) How much work is done on the gas in the process? (Use any variable or symbol stated above along with the following as necessary: n and R.) W = (b) How is the temperature of the gas related to its volume during this process? (Do not substitute numerical values; use variables only. Use the following as necessary: n, R, V, Vi, and P.) T = Need Help? Read It
Argon (molar mass 40 kg/kmol) compresses reversibly in an adiabatic system from 5 bar, 25 °C to a volume of 0.2 m If the initial volume occupied was 0.9 m calculate the final pressure in bar to 2 decimal places.. Assume nitrogen to be a perfect gas and take cv 0.3122kJ/kgK. Question 12 of 84 A Moving to another questlon will save this response.
estion Completion Status: QUESTION 26 Carbon dioxide (molar mass 44 kg/kmol) expands reversibly in a perfectly thermally insulated cylinder from 3.7 bar, 220 °C to a volume of 0 085 m If the initial volume OCcupied was 0 02 m calculate the gas constant to 3 decimal places. Assume nitrogen to be a perfect gas and take cv = 0 63 k J/kg K QUESTION 27 High-P Low-P Lurh
3
Carbon Dioxide is contained in a piston-cylinder assembly and undergoes a cycle made of the fol- lowing processes: • Process 1-2: Constant volume from 1 bar, 300 K to 600 K • Process 2–3: Polytropic expansion with n=k until P3 = P1 • Process 3-1: Isobaric compression (a) Sketch the cycle on p-v and T-v coordinates (b) Determine the work and heat transfer in each process, in kJ/kg (c) Determine the type of cycle that this is. If it is a power cycle, compute the thermal efficiency. Otherwise, compute the coefficient of performance for a heat pump cycle.
. Suppose that a room containing 1500 cubic feet of air is originally free of carbon monoxide (CO). Beginning at time t = 0, cigarette smoke containing 5% CO is introduced into the room at a rate of 0.4 cubic feet per minute. The well-circulated smoke and air mixture is allowed to leave the room at the same rate. Let Q(t) be the amount of CO in the room (in cubic feet) after t minutes. Write down an initial value problem for Q(t) and solve for Q(t).
Please do not rely too much on chatgpt, because its answer may be wrong. Please consider it carefully and give your own answer. You can borrow ideas from gpt, but please do not believe its answer.Very very grateful!
Q. - one kg of um ideal gas (R = 287 K irreversible process from Stelte - 0 [1 bar, 300 k] to State - [2 bar, 300k] The entropy change (S2-S1) J kgk
Identify whether the given property is a state or path function: Work Heat Volume Pressure Temperature
3. Ten Ibm of an ideal gas is compressed in a piston-cylinder arrangement to 1/10 of its initial volume. The ideal gas has a molecular mass (M) of 25 and the ideal gas heat capacity is given by C, = 0.4 + 0.3 x 103 T-0.2 x 106 T² Btu/(lbm °R) where Tis in Rankine. If the initial state 1 is 5 psi and 80° F and the process is polytropic with n=1,3, what is the final (state 2) pressure in psi (8%), the final temperature in °R (8%), the work done in Btu (10%), and the internal energy change (rigorous integration of C. from Tj to T2 is required) (12%), and the heat transfer in Btu (2%) for the process? 人3 13. 1.3 3-R+V B20x (4) 20x0"- 1.3 = 399.1 Psi it
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