Use a t-test to test the claim about the population mean u at the given level of significance a using the given sample statistics. Assume the population is normally distributed. Claim: u28200; a = 0.01 Sample statistics: x= 7900, s=420, n= 22 What are the null and altemative hypotheses? O A. Ho: usS 8200 H:u> 8200 O B. Ho: u28200 Hu<8200 OC. Ho: u#8200 Hu= 8200 O D. Ho: H= 8200 H, u#8200
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- Use technology to help you test the claim about the population mean, μ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: μ> 1170; x = 0.08; a=207.79. Sample statistics: x= 1198.51, n = 250 Identify the null and alternative hypotheses. Choose the correct answer below. OA. Ho: 21170 H₂H 1198.51 H:Hs 1198.51 Calculate the standardized test statistic. The standardized test statistic is (Round to two decimal places as needed.) Determine the P-value. P= (Round to three decimal places as needed.) Determine the outcome and conclusion of the test. D Ho. At the 8% significance level, there OB. Ho: s1198.51 H: 1198.51 O D. Ho: 1170 H₂: ≤1170 OF. Ho: HS1170 H₂: > 1170 enough evidence to the claim.Assume that a simple random sample has been selected and test the given claim. Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.10 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 μg/g. 3.5 6.0 6.0 6.5 20.5 7.0 11.5 20.5 11.5 18.5 Identify the value of the test statistic. Identify the P-value.Use technology to help you test the claim about the population mean, µ, at the given level of significance, a, using the given sample statistics. Assume the population is normally distributed. Claim: µ> 1170; a = 0.07; o = 212.01. Sample statistics: x= 1185.03, n= 300 Identify the null and alternative hypotheses. Choose the correct answer below. Ο Α. Ho μ2 1185.03 Ο Β. Ho : με 1185.03 Ha: µ 1185.03 O C. H μ2 1170 O D. Ho: µ> 1170 Ha: H 1185.03 Ha: µ> 1170 Ha: us1185.03 Calculate the standardized test statistic. The standardized test statistic is (Round to two decimal places as needed.) Determine the P-value. P = (Round to three decimal places as needed.) Determine the outcome and conclusion of the test. Ho. At the 7% significance level, there enough evidence to the claim.
- A data set includes data from student evaluations of courses. The summary statistics are nequals=8585, x overbarxequals=3.423.42, sequals=0.540.54. Use a 0.010.01 significance level to test the claim that the population of student course evaluations has a mean equal to 3.503.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.Use a y-test to test the claim o 35 H, o35 hir winga H, o>35 Identify the test statistic. 18.652 (Round to three decimal places as needed.) me Identify the critical value(s). nts (Round to three decimal places as needed. Use a comma to separate answers as needed.) t: C k Contents edia Library View an example Get more help - Clear all Check answer Help me solve this Plan ior SucceSE 72°F A a a 99+ P Type here to search 10/05/17 Delete PrtSc Insert F12 E11Assume that a simple random sample has been selected and test the given claim. Listed below are the lead concentrations in μg/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14 μg/g. 3.5 7.0 6.0 5.5 20.0 8.0 12.0 21.5 11.0 17.0 Identify the null and alternative hypotheses for this test. A. H0: μ=14 μg/g H1: μ<14 μg/g B. H0: μ<14 μg/g H1: μ=14 μg/g C. H0: μ=14 μg/g H1: μ>14 μg/g D. H0: μ=14 μg/g H1: μ≠14 μg/g Click to select your answer and then click Check Answer.
- Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.Listed below are the lead concentrations (in ug/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg /g. 2.96 6.45 5.99 5.51 20.53 7.45 11.97 20.46 11.52 17.54 D Identify the null and alternative hypotheses. Ho: H1: (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. V the null hypothesis. There sufficient evidence at the 0.01 significance level to V the claim that the mean lead concentration for all Ayurveda medicines…A teacher would like to determine if quiz scores improve after completion of a worksheet. The students take a pre-quiz before the worksheet and then another quiz after the worksheet. (Pre-quiz score - Post-quiz score) Assume quiz scores are normally distributed. The grades for each quiz are given below. Use a significance level of a = 0.05. H₂: Hd = 0 Ha: Hd <0 pre-quiz 12 16 17 16 11 15 12 7 15 13 post-quiz 13 16 15 16 14 15 13 9 14 15 What is the test statistic? test statistic = (Report answer accurate to 2 decimal places.) What is the p-value for this sample? p-value= (Report answer accurate to 3 decimal places.) The correct decision is to Select an answer Conclusion: Select an answer that the worksheet improved quiz scores.
- The average family size was reported as 7.2. A random sample of families in a particular school district resulted in the following family sizes: Size 4 9. 8. 4 8 9 At 1% level of significance, does the average family size different from the national average? Use traditional way of testing hypothesis. a. Mean family size of the sample: b. Sample variance: ct Test Value: d. Summarize your Interpretation: 4)Listed below are the lead concentrations (in µg/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 µg/g. 5.98 5.50 20.54 3.03 6.46 Identify the null and alternative hypotheses. Ho: H 14 H₁: μ 14 (Type integers or decimals. Do not round.) Identify the test statistic. = (Round to two decimal places as needed.) 7.45 12.01 20.47 11.48 17.53 D S Vi I. (1,0) MoreListed below are the lead concentrations (in µg/g) measured in different Ayurveda medicines. Ayurveda is a traditional medical system commonly used in India. The lead concentrations listed here are from medicines manufactured in the United States. Assume that a simple random sample has been selected. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 14.0 μg/g. 2.95 6.46 6.00 5.46 20.49 7.51 12.02 20.45 11.50 17.54 Identify the null and alternative hypotheses. Ho H₁: (Type integers or decimals. Do not round.)