Use a t-test to test the claim about the population mean p at the given level of significance a using the given sample statistics. Assume the population is normally distributed. Claim: u = 51,900; a = 0.05 Sample statistics: x = 52,622, s= 2800, n = 19 Click the icon to view the t-distribution table. TTe Stanuaruizeu tesSt Stausuc TIS KOunu to two uecimar places as Tieeueu.) What is(are) the critical value(s)? The critical value(s) is(are) (Round to three decimal places as needed. Use a comma to separate answers as needed.) Decide whether to reject or fail to reject the null hypothesis. O A. Reject Ho- There is enough evidence to reject the claim. O B. Fail to reject Ho. There is enough evidence to reject the claim. O C. Reject Ho. There is not enough evidence to reject the claim. O D. Fail to reject Ho. There is not enough evidence to reject the claim.

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**Title: Conducting a T-Test for Population Mean**

**Objective:**
To test the claim about the population mean \( \mu \) at the given level of significance \( \alpha \) using the provided sample statistics. Assume the population is normally distributed.

**Claim:**
- Population mean \( \mu \) = 51,900
- Level of significance \( \alpha \) = 0.05

**Sample Statistics:**
- Sample mean \( \bar{x} \) = 52,622
- Sample standard deviation \( s \) = 2800
- Sample size \( n \) = 19

**Instructions:**

1. **Calculate the Standardized Test Statistic:**
   - Round the result to two decimal places.

2. **Determine the Critical Value(s):**
   - Round the critical value(s) to three decimal places as needed.
   - Use a comma to separate answers if more than one value.

3. **Decision Making:**
   - Decide whether to reject or fail to reject the null hypothesis based on the standardized test statistic and critical value(s).

**Options:**

A. Reject \( H_0 \). There is enough evidence to reject the claim.

B. Fail to reject \( H_0 \). There is enough evidence to reject the claim.

C. Reject \( H_0 \). There is not enough evidence to reject the claim.

D. Fail to reject \( H_0 \). There is not enough evidence to reject the claim.

By calculating the standardized test statistic and comparing it with the critical value(s), you can determine the appropriate decision between the options provided.
Transcribed Image Text:**Title: Conducting a T-Test for Population Mean** **Objective:** To test the claim about the population mean \( \mu \) at the given level of significance \( \alpha \) using the provided sample statistics. Assume the population is normally distributed. **Claim:** - Population mean \( \mu \) = 51,900 - Level of significance \( \alpha \) = 0.05 **Sample Statistics:** - Sample mean \( \bar{x} \) = 52,622 - Sample standard deviation \( s \) = 2800 - Sample size \( n \) = 19 **Instructions:** 1. **Calculate the Standardized Test Statistic:** - Round the result to two decimal places. 2. **Determine the Critical Value(s):** - Round the critical value(s) to three decimal places as needed. - Use a comma to separate answers if more than one value. 3. **Decision Making:** - Decide whether to reject or fail to reject the null hypothesis based on the standardized test statistic and critical value(s). **Options:** A. Reject \( H_0 \). There is enough evidence to reject the claim. B. Fail to reject \( H_0 \). There is enough evidence to reject the claim. C. Reject \( H_0 \). There is not enough evidence to reject the claim. D. Fail to reject \( H_0 \). There is not enough evidence to reject the claim. By calculating the standardized test statistic and comparing it with the critical value(s), you can determine the appropriate decision between the options provided.
Use a t-test to test the claim about the population mean, \( \mu \), at the given level of significance, \( \alpha \), using the given sample statistics. Assume the population is normally distributed.

**Claim:** \( \mu = 51,900 \); \( \alpha = 0.05 \)  
**Sample statistics:** \( \bar{x} = 52,622 \), \( s = 2800 \), \( n = 19 \)

[ ] Click the icon to view the t-distribution table.

**Question:**  
What are the null and alternative hypotheses? Choose the correct answer below.

- A. \( H_0: \mu \leq 51,900 \)  
     \( H_a: \mu > 51,900 \)

- B. \( H_0: \mu \neq 51,900 \)  
     \( H_a: \mu = 51,900 \)

- C. \( H_0: \mu \geq 51,900 \)  
     \( H_a: \mu < 51,900 \)

- D. \( H_0: \mu = 51,900 \)  
     \( H_a: \mu \neq 51,900 \)

**What is the value of the standardized test statistic?**  
The standardized test statistic is [ ] (Round to two decimal places as needed.)

**What is(are) the critical value(s)?**  
The critical value(s) is(are) [ ] (Round to three decimal places as needed. Use a comma to separate answers as needed.)
Transcribed Image Text:Use a t-test to test the claim about the population mean, \( \mu \), at the given level of significance, \( \alpha \), using the given sample statistics. Assume the population is normally distributed. **Claim:** \( \mu = 51,900 \); \( \alpha = 0.05 \) **Sample statistics:** \( \bar{x} = 52,622 \), \( s = 2800 \), \( n = 19 \) [ ] Click the icon to view the t-distribution table. **Question:** What are the null and alternative hypotheses? Choose the correct answer below. - A. \( H_0: \mu \leq 51,900 \) \( H_a: \mu > 51,900 \) - B. \( H_0: \mu \neq 51,900 \) \( H_a: \mu = 51,900 \) - C. \( H_0: \mu \geq 51,900 \) \( H_a: \mu < 51,900 \) - D. \( H_0: \mu = 51,900 \) \( H_a: \mu \neq 51,900 \) **What is the value of the standardized test statistic?** The standardized test statistic is [ ] (Round to two decimal places as needed.) **What is(are) the critical value(s)?** The critical value(s) is(are) [ ] (Round to three decimal places as needed. Use a comma to separate answers as needed.)
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