Use a significance level of 0.05 to test the claim.One-way ANOVA:SourceDFSSMSSize313.5004.5005.170.011Error1613.9250.870Total1927.425Null Hypothesis, HOAlternative Hypothesis, H1Test Statistic, FP-valueSignificance levelConclusion

Let μ1,μ2 ,μ3, μ4 be the averages for 1,2,3,4 Note: According to Bartleby guidelines, expert solve…

Answered: Use a significance level of 0.05 to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use a significance level of 0.05 to test the claim. One-way ANOVA: Source DF SS MS F P Size 3 13.500 4.500 5.17 0.011 Error 16 13.925 0.870 Total 19 27.425 can you show how you worked it out please
The mean salary of federal government employees on the General Schedule is $62,493. The average salary of 21 state employees who do similar work is $60,800 with a population standard deviation of $2,700. At the .01 significance level, can it be concluded that state employees earn on average less than federal employees?
Think about doing an Independent-Measures ANOVA, Step 3. If the ANOVA Source table looks as follows, what are the MS-between, MS-within, and F-obtained? SOURCE SS df MS Fobt Between 20.22 2 ??? ??? Within 51.33 6 ??? -- Total 71.56 8 -- --
Compute a one-way ANOVA on the following data using 0.05 significance level. Group A Group B Group C 14 11 14 13 12 12 10 13 13 12 13 12 14 ANOVA Source of Variation SS df MS F P-value F crit Between Groups ? ? ? ? ? Within Groups ? ? ? Total ? ?
Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
Use a significance level of0.05 to test the claim. One-way ANOVA: Source DF SS MS Size 30 10.00 1.6 0.264 Error 50 6.25 Total 11 80 Null Hypothesis, HO Alternative Hypothesis, H1 Test Statistic, F P-value Significance level Conclusion
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An article reports that blue eyed people earn less than brown eyed people. Average blue eyed salary, $35,000, average brown eyes $37,000, p-value 0.45. Based on that reported p-value and using the common definition of "statistical significance" which is the case?
Big babies: The National Health Statistics Reports described a study in which a sample of 335 one- year-old baby boys were weighed. Their mean weight was 25.2 pounds with standard deviation 5.3 pounds. A pediatrician claims that the mean weight of one-year-old boys differs from 25 pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the a= 0.01 level of significance and the critical value method with the Critical Values for the Student's t Distribution Table. Part 1 of 5 (a) State the appropriate null and alternate hypotheses. H0 μ-25 H1: u#25 This hypothesis test is a two-tailed V test. Part 2 of 5 Find the critical value(s). Round the answer(s) to three decimal places. If there is more than one critical value, separate them with commas. Critical value(s): 2.576 , 2.576 Part: 2/5 Part 3 of 5 (b) Compute the value of the test statistic. Round the answer to at least three decimal places.
Think about doing a Repeated-Measures ANOVA, Step 2. Below is an ANOVA Source Table that is only partially filled out (just the SS and df columns are filled out). From this information, what are the F-obtained and Eta-squared? SOURCE SS df MS Fobt Between 8.00 2 Within 10.00 6 Participants 4.67 2 Error 5.33 4 Total 18.00 8 Group of answer choices F-obtained = 3.00, Eta-squared = 0.15 F-obtained = 3.00, Eta-squared = 0.60 F-obtained = 8.00, Eta-squared = 0.40 F-obtained = 8.00, Eta-squared = 0.80
Think about doing a Repeated-Measures ANOVA, Step 2. Below is an ANOVA Source Table that is only partially filled out (just the SS and df columns are filled out). From this information, what are the F-obtained and Eta-squared? SOURCE SS df MS Fobt Between 10.67 2 Within 11.33 6 Participants 8.67 2 Error 2.67 4 Total 22.00 8 Group of answer choices F-obtained = 3.00, Eta-squared = 0.60 F-obtained = 3.00, Eta-squared = 0.15 F-obtained = 8.00, Eta-squared = 0.40 F-obtained = 8.00, Eta-squared = 0.80
Complete the one-way ANOVA output table below. Then interpret the results. Give MS- and F-values with 6 decimal places and S5-values with 5 decimal places. Source df MS P-value Treatment 2 79.86667 0.01030 Error 7.333333 Total 29 The P-value statistically significant, so there some difference between at least one pair of the three groups. is is not eTextbook and Media

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Use a significance level of 0.05 to test the claim. One-way ANOVA: Source Size Error Total DF 3 16 19 SS 13.500 13.925 27.425 MS 4.500 0.870 F 5.17 0.011 Null Hypothesis, HO Alternative Hypothesis, H1 Test Statistic, F P-value Significance level Conclusion