A newspaper published an article about a study in which researchers subjected laboratory gloves to stress. Among 269 vinyl gloves, 64% leaked viruses. Among 269 latex gloves, 9% leaked viruses. Using the accompanying display of the technology results, and using a 0.05 significance level, test the claim that vinyl gloves have a greater virus leak rate than latex gloves. Let vinyl gloves be population 1. i Click the icon to view the technology results. What are the null and alternative hypotheses? OA. Ho: P₁ P2 H₁: P₁ = P2 OB. Ho: P₁ P2 H₁: P₁ P₂ OF H OC. Ho: P₁ = P₂ H₁: P₁>P2 Hin

A newspaper published an article about a study in which researchers subjected laboratory gloves to stress. Among 269 vinyl gloves, 64% leaked viruses. Among 269 latex gloves, 9% leaked viruses. Using the accompanying display of the technology results, and using a 0.05 significance level, test the claim that vinyl gloves have a greater virus leak rate than latex gloves. Let vinyl gloves be population 1. i Click the icon to view the technology results. What are the null and alternative hypotheses? OA. Ho: P₁ P2 H₁: P₁ = P2 OB. Ho: P₁ P2 H₁: P₁ P₂ OF H OC. Ho: P₁ = P₂ H₁: P₁>P2 Hin

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level.The null and alternative hypothesis would be: H0:μM=μFH1:μM<μF H0:pM=pFH1:pM<pF H0:pM=pFH1:pM>pF H0:pM=pFH1:pM≠pF H0:μM=μFH1:μM≠μF H0:μM=μFH1:μM>μF The test is: right-tailed left-tailed two-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 60 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.1 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 The test is: right-tailed left-tailed two-tailed Based on a sample of 200 people, 87% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 300 people, 276 of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 90% at the 0.05 significance level. The null and alternative hypothesis would be: Ho:µ = 0.9 Ho:p= 0.9 Ho:µ = 0.9 Ho:p = 0.9 Ho:p= 0.9 Ho:µ = 0.9 H1:µ 0.9 H1:p 0.9 H1:µ # 0.9 %3D The test is: right-tailed two-tailed left-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Submit Question JUN 4 280
A well-known brokerage firm executive claimed that 70% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 77% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is larger than 70% at the 0.025 significance level. The null and alternative hypothesis would be: Ho:µ = 0.7 Ho : µ = 0.7 Ho:p= 0.7 Họ:p = 0.7 Họ:µ = 0.7 Ho:p= 0.7 H1: µ 0.7 H1:p > 0.7 %3D %3D %3D %3D The test is: right-tailed two-tailed left-tailed The test statistic is: (to 3 decimals) The p-value is: (to 4 decimals) Based on this we: Fail to reject the null hypothesis O Reject the null hypothesis Question Help: D Post to forum Submit Question ☆吧( NOV 20 W 3D ロ

A physical therapist is interested in studying the proportion of adults that receive a physical therapy treatment plan due to sciatica. The physical therapist states the proportion of adults that receive a physical therapy treatment plan due to sciatica is less than 0.30. If we would like to test the physical therapist's claim with a hypothesis test using a significance level of α=0.10 , which of the following choices are true? Select the correct answer below: There is a 10% chance we will conclude p=0.30, but is in fact p<0.30. There is a 10% chance of rejecting the null hypothesis. There is a 10% chance we will conclude p<0.30, but is in fact p=0.30. There is a 10% chance that p<0.30
A well-known brokerage firm executive claimed that 80% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 500 people, 75% of them said they are confident of meeting their goals.Test the claim that the proportion of people who are confident is smaller than 80% at the 0.10 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: right-tailed left-tailed two-tailed The test statistic is: (to 3 decimals)The p-value is: (to 4 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.10 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is: right-tailed left-tailed two-tailed The sample consisted of 55 night students, with a sample mean GPA of 2.32 and a standard deviation of 0.05, and 55 day students, with a sample mean GPA of 2.37 and a standard deviation of 0.02.The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of adults who use the internet is greater than 0.27. Which of the following is a type I error? O A. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O C. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually different from 0.27. O D. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. Which of the following is a type II error? O A. Fail to reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is actually 0.27. O B. Reject the claim that the proportion of adults who use the internet is 0.27 when the proportion is…
A well-known brokerage firm executive claimed that 50% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 400 people, 51% of them said they are confident of meeting their goals.Test the claim that the proportion of people who are confident is larger than 50% at the 0.05 significance level.The null and alternative hypothesis would be: H0:μ=0.5H0:μ=0.5H1:μ≠0.5H1:μ≠0.5 H0:p≥0.5H0:p≥0.5H1:p<0.5H1:p<0.5 H0:μ≥0.5H0:μ≥0.5H1:μ<0.5H1:μ<0.5 H0:p=0.5H0:p=0.5H1:p≠0.5H1:p≠0.5 H0:μ≤0.5H0:μ≤0.5H1:μ>0.5H1:μ>0.5 H0:p≤0.5H0:p≤0.5H1:p>0.5H1:p>0.5 The test is: two-tailed left-tailed right-tailed The test statistic is: (to 3 decimals)The p-value is: (to 4 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Suppose the nutrition information on the package of Matilde's favorite brand of chips states that a serving size of 25 g equals about 12 chips. That means, on average, each chip should weigh 2.08 g. Matilde decides to test the accuracy of this serving size information. She plans to conduct a one-sample t-test with a significance level of a = 0.10 to test the null hypothesis, Ho: u = 2.08, against the alternative hypothesis, H1: µ # 2.08, where u is the average weight of a chip. Matilde selects a random sample of unbroken chips to weigh. She does not know the population standard deviation nor the distribution of chip weights, but she has confirmed that her sample does not contain any outliers. The summary statistics for her test are shown in the following table. Sample size Sample mean Sample standard deviation Test statistic Probability value P-value 45 2.04 0.14 -2.076 0.044 Based on these results, complete the following sentences to state the decision and conclusion of the test.…
3 24 on 25 K instructor 3255 (1).docx ! 7 A 1 option Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. Z a. What is the number of degrees of freedom that should be used for finding the critical value ₁/2? df= (Type a whole number.) b. Find the critical value a/2 corresponding to a 95% confidence level. ¹/2-0 (Round to two decimal places as needed.) c. Give a brief general description of the number of degrees of freedom. 2 D OA. The number of degrees of freedom for a collection of sample data is the number of sample values that can vary after certain restrictions have been imposed on all data values. OB. The number of degrees of freedom for a collection of sample data is the number of sample values that are determined after certain restrictions have been imposed on all data values. OC. The number of degrees of freedom for a collection of sample data is the total number of sample values. OD. The number…