uestion 34. After having made a decision on the test at the significance of a = 0.05, the most ppropriate conclusion in the context of research is A) There is not any significant difference between the species with respect to population mean brain eptide content. B) There is a significant difference between the species with respect to population mean brain peptide ontent. C) The population mean brain peptide content of skate fish is significantly greater than that of dogfish. D) The population mean brain peptide content of skate fish is not significantly greater than that of dogfish. E) The population mean brain peptide content of skate fish is exactly the same as that of dogfish. Questions 35-36. The information about head sizes was collected over 18 pilots to determine the feasibility of using cheap cardboard callipers to make the measurements, instead of metal ones which were expensive and uncomfortable. The head size of each pilot was measured once using a cardboard calliper and again using a metal calliper. Is there any mean difference between the two sets of callipers? A researcher performed two analyses using Minitab with relevant outputs below. ANALYSIS I Two-Sample T-Test and CI: Cardboard, Metal Estimation for Difference Pooled 95% CI for StDev Difference 1.61 5.68 (-2.24, 5.46) Difference T-Value DF P-Value 0.85 34 0.401 ANALYSIS II Paired T-Test and CI: Cardboard, Metal Estimation for Paired Difference 95% CI for u_difference T-Value P-Value 3.19 0.005 Mean StDev SE Mean 0.506 (0.544, 2.678) 1.611 2.146 μ_difference: mean of (Cardboard - Metal) Question 35. Let μ₁ and µ2 indicate the population mean cardboard and metal measurements of head sizes, respectively. An appropriate analysis of the above data is (A) Analysis I with alternative hypothesis Ha: µ₁ μ₂. (B) Analysis II with alternative hypothesis Ha: μ1 # µ₂. (C) Analysis I with alternative hypothesis Ha: μ₁ = μ2. (D) Analysis I with alternative hypothesis Ha: μ₁ > µ2. (E) Analysis II with alternative hypothesis Ha: µ₁ > μ₂.
uestion 34. After having made a decision on the test at the significance of a = 0.05, the most ppropriate conclusion in the context of research is A) There is not any significant difference between the species with respect to population mean brain eptide content. B) There is a significant difference between the species with respect to population mean brain peptide ontent. C) The population mean brain peptide content of skate fish is significantly greater than that of dogfish. D) The population mean brain peptide content of skate fish is not significantly greater than that of dogfish. E) The population mean brain peptide content of skate fish is exactly the same as that of dogfish. Questions 35-36. The information about head sizes was collected over 18 pilots to determine the feasibility of using cheap cardboard callipers to make the measurements, instead of metal ones which were expensive and uncomfortable. The head size of each pilot was measured once using a cardboard calliper and again using a metal calliper. Is there any mean difference between the two sets of callipers? A researcher performed two analyses using Minitab with relevant outputs below. ANALYSIS I Two-Sample T-Test and CI: Cardboard, Metal Estimation for Difference Pooled 95% CI for StDev Difference 1.61 5.68 (-2.24, 5.46) Difference T-Value DF P-Value 0.85 34 0.401 ANALYSIS II Paired T-Test and CI: Cardboard, Metal Estimation for Paired Difference 95% CI for u_difference T-Value P-Value 3.19 0.005 Mean StDev SE Mean 0.506 (0.544, 2.678) 1.611 2.146 μ_difference: mean of (Cardboard - Metal) Question 35. Let μ₁ and µ2 indicate the population mean cardboard and metal measurements of head sizes, respectively. An appropriate analysis of the above data is (A) Analysis I with alternative hypothesis Ha: µ₁ μ₂. (B) Analysis II with alternative hypothesis Ha: μ1 # µ₂. (C) Analysis I with alternative hypothesis Ha: μ₁ = μ2. (D) Analysis I with alternative hypothesis Ha: μ₁ > µ2. (E) Analysis II with alternative hypothesis Ha: µ₁ > μ₂.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Transcribed Image Text:uestion 34. After having made a decision on the test at the significance of a = 0.05, the most
ppropriate conclusion in the context of research is
A) There is not any significant difference between the species with respect to population mean brain
eptide content.
B) There is a significant difference between the species with respect to population mean brain peptide
ontent.
C) The population mean brain peptide content of skate fish is significantly greater than that of dogfish.
D) The population mean brain peptide content of skate fish is not significantly greater than that of
dogfish.
E) The population mean brain peptide content of skate fish is exactly the same as that of dogfish.
Questions 35-36. The information about head sizes was collected over 18 pilots to determine the
feasibility of using cheap cardboard callipers to make the measurements, instead of metal ones which
were expensive and uncomfortable. The head size of each pilot was measured once using a cardboard
calliper and again using a metal calliper. Is there any mean difference between the two sets of callipers?
A researcher performed two analyses using Minitab with relevant outputs below.
ANALYSIS I Two-Sample T-Test and CI: Cardboard, Metal
Estimation for Difference
Pooled 95% CI for
StDev Difference
1.61 5.68 (-2.24, 5.46)
Difference
T-Value DF P-Value
0.85 34 0.401
ANALYSIS II Paired T-Test and CI: Cardboard, Metal
Estimation for Paired Difference
95% CI for
u_difference T-Value P-Value
3.19 0.005
Mean StDev SE Mean
0.506 (0.544, 2.678)
1.611 2.146
μ_difference: mean of (Cardboard - Metal)
Question 35. Let μ₁ and µ2 indicate the population mean cardboard and metal measurements of head
sizes, respectively. An appropriate analysis of the above data is
(A) Analysis I with alternative hypothesis Ha: µ₁ μ₂.
(B) Analysis II with alternative hypothesis Ha: μ1 # µ₂.
(C) Analysis I with alternative hypothesis Ha: μ₁ = μ2.
(D) Analysis I with alternative hypothesis Ha: μ₁ > µ2.
(E) Analysis II with alternative hypothesis Ha: µ₁ > μ₂.
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