The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 116, x = 12.5, and s = 6.35. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.) State the appropriate null and alternative hypotheses. H0: ? = 15 Ha: ? ≠ 15H0: ? = 15 Ha: ? > 15 H0: ? = 15 Ha: ? ≤ 15H0: ? = 15 Ha: ? < 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject the null hypothesis. There is
The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 116, x = 12.5, and s = 6.35. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)
State the appropriate null and alternative hypotheses.
Ha: ? ≠ 15H0: ? = 15
Ha: ? > 15 H0: ? = 15
Ha: ? ≤ 15H0: ? = 15
Ha: ? < 15
Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.)
z | = | |
P-value | = |
State the conclusion in the problem context.
You may need to use the appropriate table in the Appendix of Tables to answer this question.
We have given that
Sample size n =116
Sample mean = 12.5
Standard deviation =6.35
Level of significance =0.05
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