Two transverse waves travel through a taut string. The speed of each wave if v = 22.00 m/s. A plot of the vertical position as a function of the horizontal position is shown below for the time t=0.00s. y(m) 4 Y₁(x, t) Y2(x, t) 3 2 1 0 -1 -2 -3 -4 0 2 4 6 8 10 -9 -2 12 14 a) What is the wave length of each wave? λ₁ = 12= m m b) What is the frequency of each wave? f₁ = Hz 1165 18 20 -0 x(m) f₂= Hz c) What is the maximum vertical speed of the oscillating particles of each string? V1max V 2max = m/s ✓ m/s

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Two transverse waves travel through a taut string. The speed of each wave if v = 22.00 m/s. A plot of
the vertical position as a function of the horizontal position is shown below for the time t=0.00s.
y(m)
4
Y₁(x, t)
Y2(x, t)
3
2
1
0
-1
-2
-3
-4
0 2
4
6
8 10
-9
-2
12 14
a) What is the wave length of each wave?
λ₁ =
12=
m
m
b) What is the frequency of each wave?
f₁ =
Hz
1165
18
20
-0
x(m)
f₂=
Hz
c) What is the maximum vertical speed of the oscillating particles of each string?
V1max
V
2max
=
m/s
✓ m/s
Transcribed Image Text:Two transverse waves travel through a taut string. The speed of each wave if v = 22.00 m/s. A plot of the vertical position as a function of the horizontal position is shown below for the time t=0.00s. y(m) 4 Y₁(x, t) Y2(x, t) 3 2 1 0 -1 -2 -3 -4 0 2 4 6 8 10 -9 -2 12 14 a) What is the wave length of each wave? λ₁ = 12= m m b) What is the frequency of each wave? f₁ = Hz 1165 18 20 -0 x(m) f₂= Hz c) What is the maximum vertical speed of the oscillating particles of each string? V1max V 2max = m/s ✓ m/s
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