Typed plzz A photon moving in the +x-direction, scatters off a free stationary electron. The wavelength of the incident photon is 0.0310 nm. After the collision, the electron moves at an angle a below the +x-axis, while the photon moves at an angle = 81.3° above the +x-axis. (For the purpose of this exercise, assume that the electron is traveling slow enough that the non-relativistic relationshipbetween momentum and velocity can be used.)(a) What is the angle a (in degrees)?47.21What is the shift in wavelength of the photon due to the scattering? How can you use momentum conservation in the horizontal and vertical directions to determine the angle? ° counterclockwisefrom the +x-axis(b) Determine the speed of the electron (in m/s).m/s

Consider the speed of light in vacuum is c=3∗108m/sconsider the mass of the electron is…

Answered: A photon moving in the +x-direction,…

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