Needs Complete typed solution with 100 % accuracy otherwise skip if you can't give complete solution i vill definitely upvote you for complete solution. FigureF₂ - 125 N20260°60⁰F₁ = 400 N1 of 1Part ADetermine the magnitude of the resultant force. (Figure 1)Express your answer to three significant figures and include the appropriate units.FR =SubmitPart Ba =SubmitPart CDetermine the coordinate direction angle of the resultant force.Express your answer using three significant figures.ID ΑΣΦSubmitPart DValueRequest Answer7=SubmitRequest AnswerDetermine the coordinate direction angle of the resultant force.Express your answer using three significant figures.IVL]ΑΣΦΠRequest AnswerBCRequest Answer(3 *?recUnitsDetermine the coordinate direction angle y of the resultant force.Express your answer using three significant figures.ΤΠ ΑΣΦrecE'?

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Answered: e F₂= 125 N 60 60⁰ F₁ = 400 N 1 of 1…

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Topic : Numerical integration 3.) mid-ordinate rule
For example, dimensional analysis could be used to determine the number of nickels in 3432.35 dollars. 34 dellar • To begin, write down the starting value, 3432.35 dollars. This can also be written as a fraction: Next, convert dollars to cents. This conversion involves a simple conversion factor: delar Note that the "dollar" unit should appear on the bottom of this conversion factor, since "dollars" appears on the top of the starting value. • Finally, convert cents to nickels. This conversion also involves a simple conversion factor. . This time "cents" should be on the bottom of the conversion factor, S centa since it was on top of the previous conversion factor. • Combining these expressions gives us 1 nickel 5 centa 3432.35 dollars ) (100 cente 1 dollar • Finally, cancel units. Since dollars are divided by dollars, and cents are divided by cents, both of these units can be canceled. Multiplying through gives the final result: 1 nickel 5 centis 3432.35 dollars 100 conts 68, 647…
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The same projectile experiment was conducted as you did in class. A racquet ball rolls down a track, leaves the track at an initial height of 0.961m above floor, with an exit speed Vexit 1.40m/s at an angle exit 7.46°. The landing spot was repeatedly measured for ten times, and the racquet ball's horizontal range data is provided below. Data run = Landing spot (m) 1 2 0.585 0.590 3 4 0.595 0.590 5 6 0.585 0.580 7 0.580 8 = 9 10 0.585 0.580 0.575
This solution does not make sense as it does not look lik you used the correct formula for range.
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What would be the new graph?