Two separate samples of subjects provide the following set of data. Is there a significant difference between the samples? Go through the steps of nypothesis testing using a two-tailed test and alpha = .05. X1 ("Control") X2 (“Treated") nį = 10 n2 = 15 %3D M1 = 3.5 M2 = 2.5 SS1 = 12.5 SS2 = 15.1
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- I have asked this question twice and both times it has been wrong The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use ? = 0.01 and assume normality. n = 44, Σd = 224, Σd2 = 6268(a) Find t. (Give your answer correct to two decimal places.)The following data were obtained from a repeated-measures study comparing three treatment conditions. Use a repeated-measures ANOVA with alpha = .05 to determine whether there are significant mean differences among the three treatments.Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120
- Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 356 of the 579 randomly selected wildfires looked at in the south were caused by humans while 322 of the 597 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for the difference between two population proportions b. The null and alternative hypotheses would be: Ho: p1 p2 v (please enter a decimal) H1: p1 V p2 v (Please enter a decimal) c. The test statistic z v = 2.620 (please show your answer to 3 decimal places.) d. The p-value = 0.0213 e. The p-value is >v a f. Based on this, we should reject g. Thus, the final conclusion is that ... (Please show your answer to 4 decimal places.) |the null hypothesis. O The results are statistically significant at a = 0.01, so there is sufficient evidence to conclude that the proportion of the 579…Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 356 of the 579 randomly selected wildfires looked at in the south were caused by humans while 322 of the 597 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion b. The null and alternative hypotheses would be: Ho: p1 p2 v (please enter a decimal) H1: p1 p2 v (Please enter a decimal) c. The test statistic z 2.619 (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The results are statistically significant at a = 0.01, so there is sufficient evidence to conclude that the proportion of the 579 wildfires that were caused by…Alpha equals 0.01 level of significance for the given sample data.
- Use the attached image to answer the question: Use the data above to construct a bivariate table and explore if there is an association between one’s education and attitudes toward cohabitation. Is there an association? Describe the pattern of association. Assuming that this is a random sample, test a hypothesis (use α = 0.01) that there is an association between one’s education and attitudes toward cohabitation in the population. Show all your work (state the hypotheses, find the critical value, compute the test statistics, state a conclusion) and write one sentence summarizing the results. (Extra-credit: find the p-value). Is this association weak, moderate or strong? Compute and interpret the appropriate statistic.A repeated-measures related samples study is used to compare two treatments with a sample of n=4 participants. These data produces Mp=3 with SS==48 for the set of difference scores. What is the repeated-measures t statistic for these data? A. 3/4=0.75 B. 3/ square root 3 = 1.73 C. 3/16=0.19 D. 3/2=1.50The z-statistic for the difference between the tvlo sample proportions is 5.266 with a P- value of 0.00000014. What conclusion could you make about the difference between the two population proportions if the level of significance is set to 0.05? O The difference is not statistically significant because the sample proportion difference of 0.05 is equal to the significance level of 0.05 The difference is statistically significant because the P-value of 0.00000014 is less than the significance level of 0.05. O The difference is statistically significant because the z-statistic of 5.266 is greater than the significance level of 0.05. O The difference is not statistically significant because the significance level of 0.05 is greater than the P-value of 0.00000014.
- The yield of alfalfa from a random sample of six test plots is 1.4, 1.6, 0.9, 1.9, 2.2,and 1.2 tons per acre. Assume the data can be looked upon as a sample from anormal population. Test at the 0.05 level of significance whether this supports thecontention that the average yield for this kind of alfalfa is 1.5 tones per acre.The following data were collected from a Repeated-Measures study. Perform an ANOVA. Use Instructions: Use the data collected to compute the values listed in Table#1. data @.05 person Trial 1 Table #1 1. 2. 3. 4. 6. 7. 8. 9. 10. 11 12. A B C D E Df between Df within SS total SS between subjects SS error Df between subjects Df error 0 1 0 MS error 4 HSD APA summary 0 F ratio (computed) Trial 2 0 3 1 F (critical) as reported on F ratio table 5 1 Trial 3 6 6 6 8 4The corrosive effects of various soils on coated and uncoated steel pipe was tested by using a dependent sampling plan. The data collected are summarized below, where d is the amount of corrosion on the coated portion subtracted from the amount of corrosion on the uncoated portion. Does this random sample provide sufficient reason to conclude that the coating is beneficial? Use ? = 0.01 and assume normality. n = 44, Σd = 224, Σd2 = 6268(a) Find t. (Give your answer correct to two decimal places.) (ii) Find the p-value. (Give your answer correct to four decimal places.) (b) State the appropriate conclusion. Reject the null hypothesis, there is significant evidence that the coating is beneficial.Reject the null hypothesis, there is not significant evidence that the coating is beneficial. Fail to reject the null hypothesis, there is significant evidence that the coating is beneficial.Fail to reject the null hypothesis, there is not significant evidence that the coating is beneficial.