7. For the preceding problem you should find that there are significant differences among the three treatments. The primary reason for the significance is that the mean for treatment III is substantially larger than the means for the other two treatments. To create the following data, we started with the values from problem 6 and subtracted 3 points to each score in treatment III. Notice that subtracting a constant causes the mean to change but has no influence on the variability of the sample. În the resulting data, the mean differences are much smaller than those in problem 6. Treatment III 3 3 N = 12 7 G = 48 3 1 7 EX = 236 1 5 3 M = 3 M = 4 M = 5 T = 20 SS = 16 T = 16 T = 12 SS = 8 SS = 12 II %3D
7. For the preceding problem you should find that there are significant differences among the three treatments. The primary reason for the significance is that the mean for treatment III is substantially larger than the means for the other two treatments. To create the following data, we started with the values from problem 6 and subtracted 3 points to each score in treatment III. Notice that subtracting a constant causes the mean to change but has no influence on the variability of the sample. În the resulting data, the mean differences are much smaller than those in problem 6. Treatment III 3 3 N = 12 7 G = 48 3 1 7 EX = 236 1 5 3 M = 3 M = 4 M = 5 T = 20 SS = 16 T = 16 T = 12 SS = 8 SS = 12 II %3D
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
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Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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make it so i could copy and paste it
![7. For the preceding problem you should find that there
are significant differences among the three treatments.
The primary reason for the significance is that the mean
for treatment III is substantially larger than the means
for the other two treatments. To create the following
data, we started with the values from problem 6 and
subtracted 3 points to each score in treatment III. Notice
that subtracting a constant causes the mean to change
but has no influence on the variability of the sample.
In the resulting data, the mean differences are much
smaller than those in problem 6.
Treatment
II
3
3
N = 12
5
7
G = 48
3
1
7
EX = 236
%3D
1
3
M = 3
M = 4
М — 5
T = 12
T = 16
T = 20
SS = 8
SS = 12
SS = 16
%3D
y](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a3888d7-5a4e-4f8c-aec4-246db7942ffd%2F0b840755-dc27-4bb0-bd24-9c14346c8e02%2Ffuors7q_processed.png&w=3840&q=75)
Transcribed Image Text:7. For the preceding problem you should find that there
are significant differences among the three treatments.
The primary reason for the significance is that the mean
for treatment III is substantially larger than the means
for the other two treatments. To create the following
data, we started with the values from problem 6 and
subtracted 3 points to each score in treatment III. Notice
that subtracting a constant causes the mean to change
but has no influence on the variability of the sample.
In the resulting data, the mean differences are much
smaller than those in problem 6.
Treatment
II
3
3
N = 12
5
7
G = 48
3
1
7
EX = 236
%3D
1
3
M = 3
M = 4
М — 5
T = 12
T = 16
T = 20
SS = 8
SS = 12
SS = 16
%3D
y
![b. Use an ANOVA with a = .05 to determine
whether there are any significant differences
among the three treatment means. (Does your
answer agree with your prediction in part a?)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a3888d7-5a4e-4f8c-aec4-246db7942ffd%2F0b840755-dc27-4bb0-bd24-9c14346c8e02%2F1k5zhpi_processed.png&w=3840&q=75)
Transcribed Image Text:b. Use an ANOVA with a = .05 to determine
whether there are any significant differences
among the three treatment means. (Does your
answer agree with your prediction in part a?)
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