2x be17eX +l2=O

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Question
The image contains the mathematical equation:

\[ 6e^{2x} - 17e^x + 12 = 0 \]

This is an exponential equation, which can be solved by substituting \( e^x = y \), turning it into a quadratic equation in terms of \( y \):

\[ 6y^2 - 17y + 12 = 0 \]

Solving this quadratic equation will give the values of \( y \), which can then be used to find \( x \) using the inverse of the exponential function.
Transcribed Image Text:The image contains the mathematical equation: \[ 6e^{2x} - 17e^x + 12 = 0 \] This is an exponential equation, which can be solved by substituting \( e^x = y \), turning it into a quadratic equation in terms of \( y \): \[ 6y^2 - 17y + 12 = 0 \] Solving this quadratic equation will give the values of \( y \), which can then be used to find \( x \) using the inverse of the exponential function.
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