Two nitro (NO2) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO2 group can have is required to be a multiple of €, where € = 1.0 × 1024 J. In other words, each NO2 group could have & of rotational kinetic energy, or 2ɛ, or 3%, and so forth - but it cannot have just any old amount of rotational kinetic energy. Suppose the total rotational kinetic energy in this system is initially known to be 87. Then, some heat is removed from the system, and the total rotational kinetic energy falls to 59. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol. Two rotating NO2 groups bonded to a surface. x10 ☐ ☐ 1 G
Two nitro (NO2) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they can rotate (see sketch at right). It turns out that the amount of rotational kinetic energy each NO2 group can have is required to be a multiple of €, where € = 1.0 × 1024 J. In other words, each NO2 group could have & of rotational kinetic energy, or 2ɛ, or 3%, and so forth - but it cannot have just any old amount of rotational kinetic energy. Suppose the total rotational kinetic energy in this system is initially known to be 87. Then, some heat is removed from the system, and the total rotational kinetic energy falls to 59. Calculate the change in entropy. Round your answer to 3 significant digits, and be sure it has the correct unit symbol. Two rotating NO2 groups bonded to a surface. x10 ☐ ☐ 1 G
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter9: Liquids, Solids, And Materials
Section: Chapter Questions
Problem 119QRT
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Transcribed Image Text:Two nitro (NO2) groups are chemically bonded to a patch of surface. They can't move to another location on the surface, but they
can rotate (see sketch at right).
It turns out that the amount of rotational kinetic energy each NO2 group can have is required to be a multiple of €, where
€ = 1.0 × 1024 J. In other words, each NO2 group could have & of rotational kinetic energy, or 2ɛ, or 3%, and so forth - but it
cannot have just any old amount of rotational kinetic energy.
Suppose the total rotational kinetic energy in this system is initially known to be 87. Then, some heat is removed from the
system, and the total rotational kinetic energy falls to 59. Calculate the change in entropy.
Round your answer to 3 significant digits, and be sure it has the correct unit symbol.
Two rotating NO2 groups
bonded to a surface.
x10
☐ ☐
1
G
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