Two long, parallel wires carry equal currents in opposite directions. The radius of each wire is a, and the distance between the centers of the wires is d. Show that if the magnetic flux within the wires themselves can beignored, the self-inductance of a length l of such a pair of wires isL = µ0 l π ln d − a a . (Hint: Calculate the magnetic flux through a rectangle oflength l between the wires and then use L = NΦ/I .)
Two long, parallel wires carry equal currents in opposite directions. The radius of each wire is a, and the distance between the centers of the wires is d. Show that if the magnetic flux within the wires themselves can beignored, the self-inductance of a length l of such a pair of wires isL = µ0 l π ln d − a a . (Hint: Calculate the magnetic flux through a rectangle oflength l between the wires and then use L = NΦ/I .)
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Two long, parallel wires carry equal currents in opposite directions. The radius of each wire is a, and the distance between the centers of the wires is d. Show that if the magnetic flux within the wires themselves can be
ignored, the self-inductance of a length l of such a pair of wires is
L = µ0 l π ln d − a a . (Hint: Calculate the magnetic flux through a rectangle of
length l between the wires and then use L = NΦ/I .)
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