Consider a conducting ring of radius a and resistance R. Next, we place the ring from part a in a time-varying magnetic field given by  B = (B0 (1 − t/T)  0 < t ≤ T Calculate the power dissipated due to the resistance of the loop

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A: length of the rod, L=13.0mspeed of the rod towards the north, v=29m/smagnetic field,

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A: Magnetic field, B = 0.610 TVoltage, E = 0.123 V Time, t = 1.19 sInitial area, a = 0.600 m^2Final…

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A: 18 V

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A: Please see the answer below

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Q: Calculate the magnetic flux through the loop.

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A: Flux = B.A

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Q: where Bo and ) are constants. If the loop has resistance R, show that there is a current in the loop…

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