A square loop of wire with edge length a sits in a uniform magnetic field as shown in figure 2, where the magnitude of the magnetic field varies with time t according to B = Boe¬², В %3D where Bo and ) are constants. If the loop has resistance R, show that for small times t, the power dissipated by the loop is approximately given by a*B?(2A +w²)²t² P(t) = %3D R
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- The Hall effect can be used to determine the density of mobile electrons in a conductor. A thin strip of the material being investigated is immersed in a magnetic field and oriented so that its surface is perpendicular to the field. In a particular measurement, the magnetic field strength was 0.735 T, the strip was 0.101 mm thick, the current along the strip was 2.95 A, and the Hall voltage between the strip's edges was 2.95 mV. Find the density n of mobile electrons in the material. The elementary charge is 1.602 x 10-19 C. 1.56 x104 n 3= -3 IncorrectDesign a current loop that, when rotated in a uniform magnetic field of strength 0.67 T, will produce an emf E = E, sin(wt), where E, = 110 V and w = 120n rad/s. First, choose the number of turns the loop should have. (Enter a positive integer less than 100.) turns Then calculate the needed area of the loop (in m2). (Use the number of turns you entered above.) m2A strip of copper 220 um thick and 4.70 mm wide is placed in a uniform magnetic field of magnitude B = 0.96 T, that is perpendicular to the strip. A currenti- 25 Ais then sent through the strip such that a Hall potential difference Vappears across the width. Calculate V. (The number of charge carriers per unit volume for copper is 8.47 x 102 electrons/m) Number Units
- A current I = 3 A is passed through a wire. A second wire of length L = 1 m is moving with velocity v= 285.4 m s¨¹ at a distance d=1 cm perpendicular to the magnetic field generated by the first wire (see sketch below). Calculate the current in the circuit that includes the second wire and a stationary piece of wire (green in the sketch below). Take the resistance in the circuit to be 10 Q2 (Ohm). Consider the magnetic field B to be constant over the range of motion of the second wire (i.e. d » 1 ). For the permeability of vacuum take μo = 1.3×10-6 NA². Provide your answer in milliamperes (mA). Enter your answer in the box below. Wire 1 Wire 2 اد Wire loopQ.A) A constantan wire of length 12 m and having a cross sectional area 1.4x10-4 m2 is converted into 3-turn circular loop. It is connected to a voltage of 0.160 V. If the loop is placed in a uniform magnetic field of magnitude 0.66 T at an angle of 64˚, then calculate torque in the circular loop? (The resistivity (ρ) of constantan= 49 x10 -8 Ω.m.)A cube of edge length = 4.60 cm is positioned as shown in the figure below. A uniform magnetic field given by B = (6.5 î+ 4.0 ĵ + 3.0 k) T exists throughout the region. B # i (a) Calculate the magnetic flux through the shaded face. mWb (b) What is the total flux through the six faces? mWb
- Given: B = 5 * 10-5 T ẑ; σ = 4 (Ohm-meters)-1 (conductivity) a) Assume that seawater is moving at a constant velocity v = v0 ŷ and that the Earth’s magnetic field is along the ẑ-direction. Calculate the electric current density J produced by the magnetic force. Hint: first compute the force per unit charge, F/q, and then use the relationship J = σ(F/q). b) Derive the equation of motion of a cylindrical differential volume element of base area δA and height δh parallelto the direction of J. Assume that seawater has a known volumetric mass density ρ. Show that this equation implies that the velocity satisfies the following differential equation:dvy/dt = vy/τwhere τ is a constant that you should write in terms of B, σ, and ρ.In a given region of space, the vector magnetic potential is given by A = x5 coszy + z(0.2+ sin zx) mWb/m. The magnetic flux passing through a square loop with 0.25 cm long edges if the loop is in the x-y plane, its center is at the origin, and its edges are parallel to the x- and y- axis?A loop of highly conducting wire is placed in a magnetic field that is increasing out of the page (through the loop) at a rate of 1.80 T/s. If the loop has an area of 0.400m^2, calculate the current flowing in Amps through the 5.00 ohm resistor.