Problem 4: A conducting rod spans a gap of length L = 0.248 m and acts as the fourth sideof a rectangular conducting loop, as shown in the figure. A constant magnetic field B = 0.75 Tpointing into the paper is in the region. The rod is moving under an external force with anacceleration a = At?, where A = 5.5 m/s*. The resistance in the wire is R = 185 Q.XXBXRandomized VariablesRLL = 0.248 mXXXB = 0.75 TXXXA = 5.5 m/sR= 185 QXPart (a) Express the magnitude of the magnetic flux going through the loop, , in terms of B, x and L.78HOMEAВd56h* 12 31m-ENDvol BACKSPACE DEL CLEARSubmitHintFeedbackI give up!Part (b) Express the speed of the rod, v, in terms of A and t. Assume v = 0 at t = 0.Part (c) Express the position of the rod, x, in terms of A and t. Assume x = 0 at t = 0.Part (d) Express the derivative of the magnetic flux, do/Part (e) Express the magnitude of the emf induced in the loop, ɛ, in terms of B, L. A and t.Part (f) Express the current induced in the loop, I, in terms of ɛ and R.Part (g) Express the current induced in the loop, I, in terms of B, L, A, t, and R.Part (h) Calculate the numerical value of I at t= 2s in A.in terms of B, A, L and t.www

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