Two isomers of C2H2F2 are shown. Circle the one that you would you expect to have the highest boiling point and explain your reasoning. H. H. H. F isomer A isomer B

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### Comparing Boiling Points of C₂H₂F₂ Isomers

**Question:**
Two isomers of C₂H₂F₂ are shown. Circle the one that you would expect to have the highest boiling point and explain your reasoning.

**Isomer Structures:**

- **Isomer A:**
  ```
     F     H
      \   /
       C=C
      /   \
     H     F
  ```
- **Isomer B:**
  ```
     H     H
      \   /
       C=C
      /   \
     F     F
  ```

**Explanation:**
When analyzing boiling points of isomers, it is important to consider factors such as molecular structure, intermolecular forces, and symmetry. 

1. **Intermolecular Forces:**
   - Isomer A features dipole interaction because of the polar nature of the C-F bond.
   - Isomer B likely has stronger dispersion forces due to the greater surface area for temporary dipoles, given that both sides have fluorine atoms, augmenting Van der Waals forces.

2. **Molecular Symmetry:**
   - Isomer A has a less symmetrical structure which can influence the intermolecular forces differently compared to the more symmetrical Isomer B.

3. **Polarity Contribution:**
   - Isomer A can have a net dipole moment due to asymmetrical F and H arrangement, possibly resulting in a higher boiling point due to dipole-dipole interactions.

Considering these points, **Isomer A** might have the higher boiling point because the presence of polar C-F bonds and asymmetry could lead to significant dipole-dipole interactions that require more energy to break during the phase transition from liquid to gas.

**Graphical Representation:**
Unfortunately, no graphs or charts were provided in the image to further explain the concepts visually.

*Note: The final conclusion should be backed by experimental data to validate the theoretical reasoning provided.*

---
Transcribed Image Text:--- ### Comparing Boiling Points of C₂H₂F₂ Isomers **Question:** Two isomers of C₂H₂F₂ are shown. Circle the one that you would expect to have the highest boiling point and explain your reasoning. **Isomer Structures:** - **Isomer A:** ``` F H \ / C=C / \ H F ``` - **Isomer B:** ``` H H \ / C=C / \ F F ``` **Explanation:** When analyzing boiling points of isomers, it is important to consider factors such as molecular structure, intermolecular forces, and symmetry. 1. **Intermolecular Forces:** - Isomer A features dipole interaction because of the polar nature of the C-F bond. - Isomer B likely has stronger dispersion forces due to the greater surface area for temporary dipoles, given that both sides have fluorine atoms, augmenting Van der Waals forces. 2. **Molecular Symmetry:** - Isomer A has a less symmetrical structure which can influence the intermolecular forces differently compared to the more symmetrical Isomer B. 3. **Polarity Contribution:** - Isomer A can have a net dipole moment due to asymmetrical F and H arrangement, possibly resulting in a higher boiling point due to dipole-dipole interactions. Considering these points, **Isomer A** might have the higher boiling point because the presence of polar C-F bonds and asymmetry could lead to significant dipole-dipole interactions that require more energy to break during the phase transition from liquid to gas. **Graphical Representation:** Unfortunately, no graphs or charts were provided in the image to further explain the concepts visually. *Note: The final conclusion should be backed by experimental data to validate the theoretical reasoning provided.* ---
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