B5 Part CWhat is the net work Wnet done on the block by the two forces?Express your answer numerically, in joules.VO ΑΣΦ199 ?Wnet =JSubmitRequest AnswerPart DDetermine the change K₁ - K₁ in the kinetic energy of the block as it moves from x₁ =-5.00 cm to xf = 6.00 cm.Express your answer numerically, in joules.View Available Hint(s)195| ΑΣΦ?K₁ - K₁=J Two forces, of magnitudes F₁ = 85.0 N and F₂ = 35.0N, act in opposite directions on a block, which sitsatop a frictionless surface, as shown in the figure.(Figure 1)Initially, the center of the block is at position= -5.00 cm. At some later time, the block hasmoved to the right, and its center is at a new position,z = 6.00 cm.Figure7₂< 1 of 1 >

Given that, The magnitude of the forces are F1=85NF2=35N the initial position of the box is…

Two forces, of magnitudes F1 = 85.0 N and F₂ = 35.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position = -5.00 cm. At some later time, the block has moved to the right, and its center is at a new position, z = 6.00 cm. Figure < 1 of 1

Two forces, of magnitudes F1 = 85.0 N and F₂ = 35.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position = -5.00 cm. At some later time, the block has moved to the right, and its center is at a new position, z = 6.00 cm. Figure < 1 of 1