Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The angles made by the forces with horizontal are equal to 40 degrees. The magnitudes of the forces are F1= 59 0 N and F2 = 49.0 N. The coefficient of kinetic friction between the block and the surface is 0.1.
Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The angles made by the forces with horizontal are equal to 40 degrees. The magnitudes of the forces are F1= 59 0 N and F2 = 49.0 N. The coefficient of kinetic friction between the block and the surface is 0.1.
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
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Two forces, F1 and F2, act on the 7.00-kg block shown in the drawing. The angles made by the forces with horizontal are equal to 40 degrees. The magnitudes of the forces are F1= 59 0 N and F2 = 49.0 N. The coefficient of kinetic friction between the block and the surface is 0.1.

Transcribed Image Text:**1. Show all work in detail:** Two forces, \( F_1 \) and \( F_2 \), act on the 7.00-kg block shown in the drawing. The angles made by the forces with the horizontal are equal to \( 40^\circ \). The magnitudes of the forces are \( F_1 = 59.0 \, \text{N} \) and \( F_2 = 49.0 \, \text{N} \). The coefficient of kinetic friction between the block and the surface is 0.1.
a. Draw a free body diagram to show all forces and their components.
b. Determine the kinetic friction force.
c. What is the horizontal acceleration (magnitude and direction) of the block?
**Diagram Explanation:**
The diagram includes a block on a flat surface. Two forces, \( F_1 \) and \( F_2 \), are applied at an angle of \( 40^\circ \) relative to the horizontal. \( F_1 \) is directed to the right, and \( F_2 \) is directed to the left. Component forces can be derived from these angles for calculation purposes.
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