The figure shows an overhead view of a 0.0270 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force ₁ has a magnitude of 5.00 N and is at 0₁ = 33.0°. Force F₂ has a magnitude of 8.00 N and is at 02 = 28.0°. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity ✓ = (12.0î – 15.0)) m/s, and (c) has the varying velocity v = (10.0tî - 15.0t)) m/s, where t is time? K 0₁ 0₂

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Chapter1: Units, Trigonometry. And Vectors
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The figure shows an overhead view of a 0.0270 kg lemon half and two of the three horizontal forces that act on it as it is on a
frictionless table. Force ₁ has a magnitude of 5.00 N and is at 0₁ = 33.0°. Force ₂ has a magnitude of 8.00 N and is at 0₂ = 28.0%. In
unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0î – 15.0)) m/s,
and (c) has the varying velocity = (10.0tî - 15.0t)) m/s, where t is time?
y
(a) Number
(b) Number
(c) Number
î+
î+
î+ i
F₁
又
0₁/
0₂
x
ĴUnits
ĴUnits
Units
<
Transcribed Image Text:The figure shows an overhead view of a 0.0270 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force ₁ has a magnitude of 5.00 N and is at 0₁ = 33.0°. Force ₂ has a magnitude of 8.00 N and is at 0₂ = 28.0%. In unit-vector notation, what is the third force if the lemon half (a) is stationary, (b) has the constant velocity v = (12.0î – 15.0)) m/s, and (c) has the varying velocity = (10.0tî - 15.0t)) m/s, where t is time? y (a) Number (b) Number (c) Number î+ î+ î+ i F₁ 又 0₁/ 0₂ x ĴUnits ĴUnits Units <
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