A patient with a broken tibia has the lower half of his leg suspended horizontally by a cable attached to the center of his foot. The tension in the cable needs to exert a force of F, = 25 N horizontally for traction and F, = 30 N vertically upward to support the leg. Find the magnitude of the tension in the cable. Hint: Put the center of the patient's foot at the origin of the xy-plane. Pulley F₂ (Give your answer to one decimal place. Use symbolic notation and fractions where needed.)
A patient with a broken tibia has the lower half of his leg suspended horizontally by a cable attached to the center of his foot. The tension in the cable needs to exert a force of F, = 25 N horizontally for traction and F, = 30 N vertically upward to support the leg. Find the magnitude of the tension in the cable. Hint: Put the center of the patient's foot at the origin of the xy-plane. Pulley F₂ (Give your answer to one decimal place. Use symbolic notation and fractions where needed.)
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Transcribed Image Text:A patient with a broken tibia has the lower half of his leg suspended horizontally by a cable attached to the center of his foot.
The tension in the cable needs to exert a force of F, = 25 N horizontally for traction and F, = 30 N vertically upward to
support the leg. Find the magnitude of the tension in the cable.
Hint: Put the center of the patient's foot at the origin of the xy-plane.
Pulley
F₂
x
F₁
(Give your answer to one decimal place. Use symbolic notation and fractions where needed.)
Flension
N
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