Two different simple random samples are drawn from two different populations. The first sample consists of 40 peoplewith 22 having a common attribute. The second sample consists of 1800 people with 1288 of them having the samecommon attribute. Compare the results from a hypothesis test of P₁ = P₂ (with a 0.01 significance level) and a 99%confidence interval estimate of p₁ - P2.What are the null and alternative hypotheses for the hypothesis test?OA. Ho: P1 = P2H₁: P1 P2O D. Ho: P1 = P2H₁: P1 P2B. Ho: P1 P2H₁: P1P2OE. Ho: P1 P2H₁: P1 = P2Identify the test statistic.7(Round to two decimal places as needed.)OC. Ho: P1 P₂H₁: P1 P2OF. Ho: P1 P2H₁: P1 > P2 Two different simple random samples are drawn from two different populations. The first sample consists of 40 peoplewith 22 having a common attribute. The second sample consists of 1800 people with 1288 of them having the samecommon attribute. Compare the results from a hypothesis test of P₁ = P2 (with a 0.01 significance level) and a 99%confidence interval estimate of p₁ - P2.Identify the critical value(s).(Round to three decimal places as needed. Use a comma to separate answers as needed.)What is the conclusion based on the hypothesis test?the critical region, soThe test statistic isconclude that p₁ #P2-The 99% confidence interval is < (P₁-P2) <(Round to three decimal places as needed.)What is the conclusion based on the confidence interval?the null hypothesis. There isevidence to

With the usual notation, n1=40, x1=22 n2=1800, x2=1288 Significance level: α=0.01 Hence,…

Answered: Two different simple random samples are…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a random sample of 392 people that were tested for the Norcovirus, it was found that 314 did not have the virus. A 97% confidence interval was constructed to estimate the proportion of the population that does not have the Norcovirus. This confidence interval came out to be (0.76,0.84).
A recent study of high school students shows the percentage of females and males who have an after-school job. A simple random sample of high school students was interviewed. The students were asked whether they worked after school. Of the 250 females, 58 answered yes, as did 113 of the 380 males. Part A: Construct and interpret a 95% confidence interval for the difference in population proportions of females and males who have an after-school job. Be sure to state the parameter, check conditions, perform calculations, and make conclusion(s). Part B: Does your interval from part A give convincing evidence of a difference between the population proportions? Explain.
A sample of size 25 was taken from a very large population. Sample statistics, x¯ and s, were used to find that the 95% confidence interval was (138.616, 163.384). x¯= s=
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if n=20, x=43, and s=9, construct a confidence interval at a 98% confidence level, the data came from a normally distributed population.
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The Martin County Health Department needs to estimate the proportion of all children in the county aged 19-35 months that are completely up to date with all state-recommended immunizations. The Martin County Health Department found that 88% of a random sample of children in the county aged 19-35 months were completely up to date with all state-recommended immunizations. Find three different confidence intervals - one with sample size 228, one with sample size 402, and one with sample size 658. Assume that 88% of the children each sample are completely up to date with all state recommended immunizations. Observe how the sample size affects the margin of error and subsequently the width of each interval. Report confidence interval solutions using interval notation. Report all solutions in percent form, rounded to two decimal places, if necessary. • When n = 228, the margin of error for a 95% confidence interval is given by When n = • When n = When n = 228, a 95% confidence interval is…
A researcher surveys a group of college students to determine the negative life events that they experienced in the past 5 years and their current feeling of well-being. For N = 18 participants with 2 or fewer negative experiences, the average well-being score was X = 42 with SS = 398. For the N = 16 participants with 5 to 10 negative experiences the average score is X = 48.6 with SS = 370. Construct a 95% confidence interval for the difference between the population means for the two groups.
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Two different simple random samples are drawn from two different populations. The first sample consists of 20 people with 10 having a common attribute. The second sample consists of 2200 people with 1597 of them having the same common attribute. Compare the results from a hypothesis test of p1= p2 (with a 0.01 significance level) and a 99% confidence interval estimate of p1− p2.
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