You are working as an assistant to the dean of institutional research at your university. The dean wants to survey members of the alumni association who obtainedtheir baccalaureate degrees 5 years ago to learn what their starting salaries were in their first full-time job after receiving their degrees. A sample of 50 alumni is tobe randomly selected from the list of 2,000 graduates in that class. If the dean's goal is to construct a 90% confidence interval estimate for the population meanstarting salary, why is it not possible that you will be able to use the expression X+ Zo.05for this purpose? Explain....Why is it not possible to use the equation?O A. The population standard deviation o is not known.O B. The sample mean X might not be a whole number, but the number of students must be.OC. The sample size n is not large enough to use this expression.O D. The sample size n is too large to use this expression.

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Answered: You are working as an assistant to the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In a random sample of 250 high school students, it was found that 85.2% (213) of them later graduated. Find the 95% and 98% confidence interval for the true proportion of all high school students who graduate. Compare the two proportions.
A high school is running a campaign against the over-use of technology in teens. The committee running the campaign decides to look at the difference in social media usage between teens and adults. They take a random sample of 200 teens in their city (Group 1) and find that 85% of them use social media, and then take another random sample of 180 adults in their city (Group 2) and find that 55% of them use social media. Find a 90% confidence interval for the difference in proportions. Enter the confidence interval
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if n = 42, p = 0.6 then construct the 98% confidence interval for the population proportion.
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You want to estimate the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work. You took an SRS of 7 businesses and collected the following data for number of complaints in a year: men 1 3 2 4 6 3 5 women 8 7 6 3 5 12 15 Create a 90% confidence interval for the average difference in the number of complaints filed by women at work and the number of complaints filed by men at work (in a year). You must do this using table C. If this is a 2 sample interval, be sure to specify who is population 1 and who is population 2. If this is a matched pairs interval, be sure to state the order you subtracted your data. Once you create your interval, give a sentence explaining the meaning of the interval (what the numbers in the interval mean, NOT the meaning of 95%) in context of this problem. Round to any appropriate number of decimals.
A statistics student wants to conduct a study to determine the proportion of workers in Cititon who commute to another town for work. If the student wants a 90% confidence interval with a margin of error of 2%, how many workers should be in her sample?
The dataset "nurses" is a random sample of 1,000 cases from “Health Care Provider Credential Data” from Washington State Open Data Portal. In the sample, there are 418 CNA's and 278 of the CNA's have expired credentials. Use the statistics from the nurses dataset to answer the following question: "With 90% confidence, what percent of all CNA's on Washington State's healthcare provider list are expired?"
I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)

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