A survey of 500 randomly selected students was taken and 200 responded that they favor candidate Z for class president (p ₁ = 0.4). Just before the election, another survey of 700 students was taken and 450 students responded that theyfavor candidate Z (P 2 = 0.6429). A 98% two-proportion z confidence interval for the true difference between p ₁ and p 2 was found to be (-0.3090, -0.1767). What is the meaning of the interval in the context of the problem?O There has been no change in support for the candidate.O There has been a substantial drop in support for the candidate.O There has been a substantial gain in support for the candidate.O It is probable for the candidate to get most of the votes because support has risen more than 50%.O It is not probable for the candidate to get most of the votes because the interval is negative.

The confidence interval given is (-0.3090, -0.1767)This interval represents the range within which…

Answered: A survey of 500 randomly selected…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to statistics published by CNBC, the amount they are insured is surprising. CNBC's sample results indicate that 57 out of 84 vehicles were uninsured. Give a 95% confidence interval for the population proportion of the form p ± E where p is the point estimator of the proportion and E is the margin of error. Select one: a. The interval is 0.321 ± 0.100. b. The interval is 0.321 ± 0.084. c. The interval is 0.679 ± 0.100. d. The interval is 0.679 ± 0.131. e. The interval is 0.679 ± 0.084.
A small shop is trying to compare the proportion of consumers who prefer buying a pre-made bread and those who prefer fresh bread. They randomly sample daily consumers and asked for their opinion. The shop is then decided to construct a 90% confidence interval for the difference of population proportion and found it equal to (-0.53 , 0.30). i. based on the interval, what is the decision for testing HoP1- P2=0 against H 1:P- p270 at 5% significant levels Ocannot be determine OFail to reject the null hypothesis Reject the null hypothesis ii. using the interval, what is the decision for testing HoP1-P2=0 against H 1:P,- p,#0 at 10% significant levels OReject the null hypothesis Fail to reject the null hypothesis Ocannot be determine
Pedro was working on a report on Swiss and Austrian psychiatrists. He decided to find a 90 percent confidence interval for the difference in mean age at the time of significant psychiatric discoveries for Swiss versus Austrian psychiatrists. He found the ages at the time of psychological discovery of all the members of both groups and found the 90 percent confidence interval based on a t-distribution using a calculator. The procedure he used is not appropriate in this context because O The sample sizes for the two groups are not equal. O The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used. O Age at the time of psychological discovery occurs at different intervals in the two countries, so the distribution of ages cannot be the same. O Age at the time of psychological discovery is likely to be skewed rather than bell shaped, so the assumptions for using this confidence interval formula are not…
Sal knows that parties of people on average spend 75 minutes at their restaurant. They wonder if this average is significantly different on the weekends. They found the average time spent by the 30 parties which dined there this weekend was 82 minutes with a SD of 17 minutes. Assume an alpha of .05. The lower end of the 95% confidence interval is and the higher end of the 95% confidence interval is.
A researcher surveys a group of college students to determine the negative life events that they experienced in the past 5 years and their current feeling of well-being. For N = 18 participants with 2 or fewer negative experiences, the average well-being score was X = 42 with SS = 398. For the N = 16 participants with 5 to 10 negative experiences the average score is X = 48.6 with SS = 370. Construct a 95% confidence interval for the difference between the population means for the two groups.
A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 respondents, 13% chose chocolate pie, and the margin of error was given as ±4 percentage poits. Describe what is meant by the statement that "the margin of error was given as ±4 percentage points." (...) Choose the correct answer below. OA. The statement indicates that the study is only 4% confident that the true population percentage of people that prefer chocolate pie is exactly 13%. OB. The statement indicates that the study is 100% -4% = 96% confident that the true population percentage of people that prefer chocolate pie is 13%. OC. The statement indicates that the interval 13% ± 4% is likely to contain the true population percentage of people that prefer chocolate pie. D. The statement indicates that the true population percentage of people that prefer chocolate pie is in the interval 13% ± 4%.
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