A random sample of n₁ = 261 people who live in a city were selected and 107 identified as a "dog person." Arandom sample of n2 = 107 people who live in a rural area were selected and 62 identified as a "dog person."Find the 99% confidence interval for the difference in the proportion of people that live in a city who identifyas a "dog person" and the proportion of people that live in a rural area who identify as a "dog person."Round answers to to 4 decimal places.P1-P2<Question Help: Message instructorSubmit Question

Suppose p1 is the true population proportion of people that live in the city who identify as a “dog…

Answered: A random sample of n₁ = 261 people who…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A study was done to determine whether there is a relationship between snoring and the risk of heart disease. Among 1,105 snorers in the study, 89 had heart disease, while only 29 of 1,379 nonsnorers had heart disease. Determine a 95% confidence interval that estimates p1 − p2 = difference in proportions of snorers and nonsnorers who have heart disease. (Let p1 be the proportion of snorers and p2 be the proportion of nonsnorers. Round your answers to three decimal places.) ____to ____
A random sample of n1n1 = 236 people who live in a city were selected and 90 identified as a "dog person." A random sample of n2n2 = 103 people who live in a rural area were selected and 56 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. ___________< p1−p2p1-p2 <_____________
The New York Times conducted a nationwide poll of 1048 randomly selected 13- to 17-year-olds. to estimate the proportion of 13- to 17-year-olds who have a television in their room. We can consider the sample to be a simple random sample. Of these 1048 teenagers, 692 had a television in their room. Give a 95% confidence interval for the proportion of all people in this age group who had a TV in their room at the time of the poll, and interpret what your interval means in context. State: Plan: Do: Conclude:
In a random sample of 400 adults in a small town, 189 of them participated in some form of adult education. Find a 98% confidence interval for the population proportion of adults in the town who participate in adult education
Car and Driver Magazine tested a random sample of 9 hybrid cars and found their MPG to be 42, 51, 39, 44, 52, 48, 51, 44, and 47. Construct a 95% confidence interval for the population variance.
In a survey of 700 community college students , 481 indicated that they have read a book for personal enjoyment during the school year (based on data from the community college survey of student engagement). determine a 90% confidence interval for the proportion of community college students who have read a book for personal enjoyment during the school year. determina a 95% confidence interval for the proportion of community college students who have read a book for personal enjoyment during the school year
A random sample of 180 men indicated that 50 were smokers, and a random sample of 150 women surveyed indicated that 39 smoked. Construct a 98% confidence interval for the true difference in proportions of male and female smokers.
A recent survey of two countries in South America reports on data about foreign-born citizens. Of 500 randomly selected people in Peru, 125 reported as being born in another country; meanwhile, 75 of 800 randonly selected Argentinians reported as being foreign-born. Use this information to create a 95% confidence interval for the true difference in proportions of foreign born citizens between Peru and Argentina.
In a survey, 545 college students are randomly selected and asked whether or not they own a car. Of those surveyed, it is found that 210 own a car. Use this data to find a 99% confidence interval for the true proportion of all college students who own a car.
A random sample of n - 236 people who live in a city were selected and 81 identified as a "dog person." A random sample of n2 - 109 people who live in a rural area were selected and 60 identified as a "dog person." Find the 90% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. P1 - P2 Question Help: Message instructor Submit Question Jump to Answer
A researcher takes a random sample of 100 Americans that have never had a pet and a separate random sample of 100 Americans that are current or previous pet owners. She is interested in determining whether there is a difference in the proportion of individuals who believe in the afterlife among these two groups. She observes that 76 of the "never pet owners" and 84 of the "ever pet owners" believe in the afterlife. Determine the margin of error for a confidence interval for the difference in the two appropriate proportions at a 95% confidence level. a. The assumptions necessary to perform the calculation are not satisfied. b. 0.0837 c. 0.0719 d. 0.1103 e. 1.96
A random sample of n1n1 = 235 people who live in a city were selected and 79 identified as a "dog person." A random sample of n2n2 = 93 people who live in a rural area were selected and 67 identified as a "dog person." Find the 99% confidence interval for the difference in the proportion of people that live in a city who identify as a "dog person" and the proportion of people that live in a rural area who identify as a "dog person." Round answers to to 4 decimal places. < p1−p2<

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