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Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 39 students, she finds 5 who eat cauliflower. Obtain and interpret a 99% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method.
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- You recently sent out a survey to determine if the percentage of adults who use social media has changed from 62%, which was the percentage of adults who used social media five years ago. Of the 2283 people who responded to survey, 1635 stated that they currently use social media.a) Use the data from this survey to construct a 94% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.In a sample of 500 Canadians, it was found that 400 people preferred apple products. In a sample of 700 Americans it was found that 600 preferred apple products. Is the proportion Canadians who prefer apple products less than Americans. 1. Construct 95% confidence interval for difference of proportions. 2. From the confidence interval, do you think that the proportion of Canadians who prefer apple products is different from Americans.If n=470 and p̂ (p-hat) = 0.65, construct a 95% confidence interval.
- In a survey of 2569 adults in a recent year, 1303 say they have made a New Year's resolution. Construct 90% and 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals.In a science fair project, Emily conducted an experiment in which she tested professional touch therapists to see if they could sense her energy field. She flipped a coin to select either her right hand or her left hand, and then she asked the therapists to identify the selected hand by placing their hand just under Emily's hand without seeing it and without touching it. Among 337 trials, the touch therapists were correct 163 times. Using Emily's sample results, construct a 95% confidence interval estimate of the proportion of correct responses made by touch therapists. (round to 3 decimal places)Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 27 students, she finds 3 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. i Agresti and Coull's method for constructing confidence intervals (Round to three decimal places as needed.) O A. There is a 90% chance that the proportion of students who eat cauliflower on Jane's campus is between and O B. The proportion of students who eat cauliflower on Jane's campus is between To deal with issues such as the distribution of p not following a normal distribution, A. Agresti and B. Coull proposed a modified approach to constructing confidence intervals for a proportion. A (1 - a) • 100%…
- Professor Smith loves dark chocolate, and she would like to find out the proportion of the population that shares her preference. She randomly sampled 700 people, and 630 people chose dark chocolate. To construct a 95% confidence interval, she should use: TInterval 1-PropZInt 2-SampZInt 2-PropZInt ZInterval 2-SampTIntIn the United States, 1000 residents aged 15 or older were surveyed and 870 replied that they were satisfied with the water quality. The 90% confidence interval estimate of all U.S residents satisfied with their water quality isTo estimate the proportion of students who purchase their textbooks used, 500 students were sampled. 210 of these students purchased used textbooks. Find a 99% confidence interval for the proportion of students who purchase used text books.
