**Problem Context:**Jane intends to estimate the proportion of students on her campus who eat cauliflower. She conducted a survey involving 36 students and found that 2 of them consume cauliflower. Using Agresti and Coull’s method, it is required to obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus.**Task:**Construct and interpret the 95% confidence interval. Further, select the correct choice regarding this interval and fill in the answer boxes. The values should be rounded to three decimal places as needed.**Options:**- **A.** The proportion of students who eat cauliflower on Jane's campus is between [ ] and [ ] 95% of the time. - **B.** There is a 95% chance that the proportion of students who eat cauliflower in Jane's sample is between [ ] and [ ]. - **C.** There is a 95% chance that the proportion of students who eat cauliflower on Jane's campus is between [ ] and [ ].- **D.** One is 95% confident that the proportion of students who eat cauliflower on Jane's campus is between [ ] and [ ].

It is given that 2 students who eat cauliflower out of 36 students.

Answered: Jane wants to estimate the proportion…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

If n = 440 and p = 0.52, construct a 90% confidence interval. %3D Give your answers to three decimals
Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a 95% confidence interval estimate of the population percentage. Based on the result, does it appear that greater height is an advantage for presidential candidates? Why or why not? | Click the icon to view the table of heights. Construct a 95% confidence interval estimate of the percentage of presidents who were taller than their opponents. D%
A survey was conducted that asked 1009 people how many books they had read in the past year. Results indicated that x = 14.4 books and s= 16.6 books. Construct a 90% confidence interval for the mean number of books people read. Interpret the interval. Click the icon to view the table of critical t-values. C Construct a 90% confidence interval for the mean number of books people read and interpret the result. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to two decimal places as needed.) OA. If repeated samples are taken, 90% of them will have a sample mean between and H OB. There is a 90% probability that the true mean number of books read is between and OC. There is 90% confidence that the population mean number of books read is between and
A newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of a poll, showed that 41% would like more discussion about the family's financial situation, 11% would like to talk about school, and 43% would like to talk about religion. These and other percentages were based on a national sampling of 393 teenagers. Write the margin of error for a 90% confidence interval that estimates the proportion of all teenagers who want more family discussions about school. Round to the nearest thousandth.
Answer each question and justify all work for full You will need your z and t charts for this quiz. 1. Death penalty: A group claims that the overall feelings of the general population on the . death penalty is changing. 643 people were interviewed, and of them, 258 believed in using the death penalty. Construct a 95% confidence interval for the proportion of people that believe in the death penalty. Follow the steps below: What is the best point estimate for the proportion of people who believe in the death penalty? › (round to two decimal places)
If n=16, x¯(x-bar)=48, and s=7, construct a confidence interval at a 98% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.
1. Explain how to find a confidence interval for a population proportion using StatCrunch. 2. Explain how to find the margin of error given a confidence interval for a population proportion.
Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 27 students, she finds 3 who eat cauliflower. Obtain and interpret a 90% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. Construct and interpret the 90% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. i Agresti and Coull's method for constructing confidence intervals (Round to three decimal places as needed.) O A. There is a 90% chance that the proportion of students who eat cauliflower on Jane's campus is between and O B. The proportion of students who eat cauliflower on Jane's campus is between To deal with issues such as the distribution of p not following a normal distribution, A. Agresti and B. Coull proposed a modified approach to constructing confidence intervals for a proportion. A (1 - a) • 100%…
The National Center for Education Statistics reported that 47% of college students work to pay for tuition and living expenses. Assume that a sample of 450 colleges students was used in this study. 1. Provide a 95% confidence interval for the population proportion of college students who work to pay for tuition and living expenses. 2. Provide a 99% confidence interval for the population proportion of college students who work to pay for tuition and living expenses. 3. What happens to the margin of error as the confidence is increased from 95% to 99%? Explain why this makes sense. 4. Suppose the NCES would like to re-do their study. If they want a 95% confidence interval with a margin of error for the population proportion within ±0.03, determine the sample size they should use. Use , the sample proportion from their previous study.
If n=430 and (p-hat) = 0.67, construct a 90% confidence interval. Give your answers to three decimals
I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS