**Problem Context:**Jane intends to estimate the proportion of students on her campus who eat cauliflower. She conducted a survey involving 36 students and found that 2 of them consume cauliflower. Using Agresti and Coull’s method, it is required to obtain and interpret a 95% confidence interval for the proportion of students who eat cauliflower on Jane's campus.**Task:**Construct and interpret the 95% confidence interval. Further, select the correct choice regarding this interval and fill in the answer boxes. The values should be rounded to three decimal places as needed.**Options:**- **A.** The proportion of students who eat cauliflower on Jane's campus is between [ ] and [ ] 95% of the time. - **B.** There is a 95% chance that the proportion of students who eat cauliflower in Jane's sample is between [ ] and [ ]. - **C.** There is a 95% chance that the proportion of students who eat cauliflower on Jane's campus is between [ ] and [ ].- **D.** One is 95% confident that the proportion of students who eat cauliflower on Jane's campus is between [ ] and [ ].

It is given that 2 students who eat cauliflower out of 36 students.

Answered: Jane wants to estimate the proportion…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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