In a survey of 2591 adults in a recent​ year 1414, say they have made a New​ Year's resolution. Construct​ 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare the widths of the confidence intervals

Q: In a survey of 2224 adults in a recent​ year, 1280 say they have made a New​ Year's resolution.…

A: Obtain the 90% confidence interval for the population proportion. The 90% confidence interval for…

Q: If a 92% Confidence Interval for the Population Mean is (67.8, 78.9), find its Margin of Error.

A:

Q: survey of 2542 adults in a recent​ year, 1362 say they have made a New​ Year's resolution.…

A: From the given information we construct 90% and 95% confidence interval.

Q: It contains data on brain mass in different species versus glia-neuron ratio, the latter being a…

A: Note: Hi there! Thank you for posting the question. As your question has more than 3 parts, we have…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 2549 adults in a recent​ year, 1270 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2195 adults in a recent​ year, 1454 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 3254 ​adults, 1433 say they have started paying bills online in the last year.…

A: Given X=1433 n=3254

Q: requiring front license plates at a higher rate than owners of passenger cars. Use a 0.05…

A: a. The proportion of commercial trucks violating laws requiring front license is, Thus, the…

Q: adults in a recent​ year, 742 made a New​ Year's resolution to eat healthier.   Construct​ 90% and​…

A: The value of z at a 90% confidence level is 1.645, which can be found by using the standard normal…

Q: In a survey of 2113 adults in a recent​ year, 741 made a New​ Year's resolution to eat healthier.…

A:

Q: I want to estimate the population mean number of times people walk their dogs in a day In my…

A: Given information- Sample size, n = 5 Calculating sample mean and sample standard deviation using…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: he confidence interval was (73, 83) What was the point estimate? What was the margin of error?

A: Given: Lower limit =73 Upper limit =83 The point estimate can be calculated as: Point estimate…

Q: A business magazine conducted a survey of 751 employees who had been at their current employer for 5…

A: It is given that sample size n =751 and x = 0.295.

Q: Out of 180 randomly selected adults in the United States who were surveyed, 81 exercise on a regular…

A:

Q: In a survey of 2405 adults in a recent​ year, 1217 say they have made a New Year's resolution.…

A: Given: n=2405 x=1217

Q: When 302 college students are randomly selected and surveyed, it is found that 122 own a car. What…

A: E have to find point estimate with with confidance interval..

Q: In a survey of 793 adults, 460 say they have started paying bills online in the last year. Construct…

A: Answer: From the given data, Sample size(n) = 793 X = 460 98% confidence interval,

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: In a survey of 2552 ​adults, 1423 say they have started paying bills online in the last year.…

A: Given that, In a survey of 2552 adults, 1423 say they have started paying bills online in the last…

Q: In a survey of 2407 adults in a recent​ year,1468 say they have made a New​ Year's resolution.…

A: Given that,  Sample size, n= 2407 And X= 1468 We know that proportion, p=X/n So p= 1468/2407 p=…

Q: In a survey of 2108 adults in a recent​ year, 1305 say they have made a New​ Year's resolution.…

A:

Q: In a survey of 2000 adults in a recent​ year 1404, say they have made a New​ Year's resolution.…

A: n=2000x=1404

Q: The confidence interval was (22, 26) What was the point estimate? What was the margin of error?

A: Given confidence interval was (22, 26)

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

A:

Q: Advertising aimed at teenagers tends to contain dance-beat music, adventure, and a fast pace rather…

A: To test the given claim the appropriate hypothesis are as follows H0:p1-p2≥0.1H1:p1-p2<0.1 The…

Q: In a survey of 2334 adults in a recent​ year,1370 say they have made a New​ Year's resolution.…

A: Given n=2334 X=1370

Q: In a survey of 3292 adults, 1470 say they have started paying bills online in the last year.…

A: Using Excel formula “=NORM.S.INV(1-(0.01/2))”, the critical value for 99% confidence level is…

Q: Out of 300 people sampled, 279 had kids. Based on this, construct a 90% confidence interval for the…

A:

Q: In a survey of 3071 ​adults, 1484 say they have started paying bills online in the last year.…

A: Given, Therefore, As per z-distribution table the critical value of z at 0.01 level of significant…

Q: 90% and​ 95% confidence intervals for the population proportion. Interpret the results and compare…

A: Answer Favorable cases [x] = 1230The sample size [n] = 2105