Two 50-Hz emf having rms values of 22.6 and 33.9 volts differ in phase by an angle of 60°, the latter current lagging and its positive-going zero crossing is at 0 °. Determine the resultant emf (in wave equation) if they are connected in series. A. e₁= 49.26 sin (2750t + 0.4086) B. e= 69.66 sin (2750t + 0.4086) C. er= 49.26 sin (2760t + 0.4086) D. er= 69.66 sin (2760t + 0.4086)
Two 50-Hz emf having rms values of 22.6 and 33.9 volts differ in phase by an angle of 60°, the latter current lagging and its positive-going zero crossing is at 0 °. Determine the resultant emf (in wave equation) if they are connected in series. A. e₁= 49.26 sin (2750t + 0.4086) B. e= 69.66 sin (2750t + 0.4086) C. er= 49.26 sin (2760t + 0.4086) D. er= 69.66 sin (2760t + 0.4086)
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![Two 50-Hz emf having rms values of 22.6 and 33.9 volts differ in phase by an
angle of 60°, the latter current lagging and its positive-going zero crossing is at 0
°. Determine the resultant emf (in wave equation) if they are connected in series.
A. et = 49.26 sin (2750t + 0.4086)
B. e₁ = 69.66 sin (2750t +0.4086)
C. e=49.26 sin (2760t + 0.4086)
D.
e₁ =
e₁ = 69.66 sin (2760t + 0.4086)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe89dce7a-48f4-4c5a-9fb3-a046abba3abc%2F61b23ed3-4adf-4e5a-a7b9-a00d88d562e6%2Fbk4zunq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Two 50-Hz emf having rms values of 22.6 and 33.9 volts differ in phase by an
angle of 60°, the latter current lagging and its positive-going zero crossing is at 0
°. Determine the resultant emf (in wave equation) if they are connected in series.
A. et = 49.26 sin (2750t + 0.4086)
B. e₁ = 69.66 sin (2750t +0.4086)
C. e=49.26 sin (2760t + 0.4086)
D.
e₁ =
e₁ = 69.66 sin (2760t + 0.4086)
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