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circuit shown in Figure 12-39. 10Ω VL 0.3 H 2-39: Circuit schematic for problem 12.20.

circuit shown in Figure 12-39. 10Ω VL 0.3 H 2-39: Circuit schematic for problem 12.20.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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### Problem 12.20: Determine the Voltage \( V_L \) This problem requires the determination of the voltage \( V_L \) in the given circuit. #### Figure 12-39: Circuit Schematic for Problem 12.20 The diagram shows a simple series circuit containing the following components: - **Voltage Source**: The circuit is powered by a voltage source with an expression of \( v_s = 2 \cos 8t \). - **Resistor**: The circuit includes a resistor with a resistance of \( 10 \, \Omega \). - **Inductor**: An inductor with an inductance of \( 0.3 \, H \) is present. The inductor's voltage drop is labeled as \( V_L \). The circuit follows a straightforward arrangement where the components are connected in a loop. The positive and negative terminals of both the voltage source and inductor are clearly marked.
Transcribed Image Text:### Problem 12.20: Determine the Voltage \( V_L \) This problem requires the determination of the voltage \( V_L \) in the given circuit. #### Figure 12-39: Circuit Schematic for Problem 12.20 The diagram shows a simple series circuit containing the following components: - **Voltage Source**: The circuit is powered by a voltage source with an expression of \( v_s = 2 \cos 8t \). - **Resistor**: The circuit includes a resistor with a resistance of \( 10 \, \Omega \). - **Inductor**: An inductor with an inductance of \( 0.3 \, H \) is present. The inductor's voltage drop is labeled as \( V_L \). The circuit follows a straightforward arrangement where the components are connected in a loop. The positive and negative terminals of both the voltage source and inductor are clearly marked.
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