Two 50-Hz currents i₁ = 2.5 sin (wt - 15°) and i₂ = 3.5 sin (wt - 75°) flow in a common wire. Determine (a) their resultant i3; (b) angle between i₁ and iç. A. 13 = 6 sin (wt - 90°), 90° B. 13 = 5.22 sin (wt - 78.69°), 63.69⁰ C. 13 = 6 sin (wt - 50.5°), 35.5° D. 13 = 5.22 sin (wt - 50.5°), 35.5°
Two 50-Hz currents i₁ = 2.5 sin (wt - 15°) and i₂ = 3.5 sin (wt - 75°) flow in a common wire. Determine (a) their resultant i3; (b) angle between i₁ and iç. A. 13 = 6 sin (wt - 90°), 90° B. 13 = 5.22 sin (wt - 78.69°), 63.69⁰ C. 13 = 6 sin (wt - 50.5°), 35.5° D. 13 = 5.22 sin (wt - 50.5°), 35.5°
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![Two 50-Hz currents i₁ = 2.5 sin (wt -15°) and i₂= 3.5 sin (wt - 75°) flow in a
common wire. Determine (a) their resultant i3; (b) angle between ₁ and i3 .
A. 13 = 6 sin (wt - 90°), 90°
B. 13 = 5.22 sin (wt - 78.69°), 63.69°
C. 13 = 6 sin (wt - 50.5°), 35.5°
D.
13 = 5.22 sin (wt - 50.5°), 35.5°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe89dce7a-48f4-4c5a-9fb3-a046abba3abc%2F68626a62-2965-41c8-98b1-6e553047fa55%2Faxwa1yk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Two 50-Hz currents i₁ = 2.5 sin (wt -15°) and i₂= 3.5 sin (wt - 75°) flow in a
common wire. Determine (a) their resultant i3; (b) angle between ₁ and i3 .
A. 13 = 6 sin (wt - 90°), 90°
B. 13 = 5.22 sin (wt - 78.69°), 63.69°
C. 13 = 6 sin (wt - 50.5°), 35.5°
D.
13 = 5.22 sin (wt - 50.5°), 35.5°
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