This new estimate for V2 substituted back to the equation will produce the second estimate: V 2.2 1 = 0.3603-146.3° -(1.9612/101.3°)(120°) 1.9612-78.8° 0.8797/+8.499° =0.8412-8.499° The third iteration will be V 2.3 1 0.3603-146.3° (1.9612/101.3°)(120°)] 1.9612-78.8° 0.8412/+8.499° = 0.8345-8.962° The fourth iteration will b 1 V 2,4 = 0.3603-146.3° -(1.9612/101.3°)(120°) 1.9612-78.8° 0.8345/+8.962 = 0.8320-8.962°
This new estimate for V2 substituted back to the equation will produce the second estimate: V 2.2 1 = 0.3603-146.3° -(1.9612/101.3°)(120°) 1.9612-78.8° 0.8797/+8.499° =0.8412-8.499° The third iteration will be V 2.3 1 0.3603-146.3° (1.9612/101.3°)(120°)] 1.9612-78.8° 0.8412/+8.499° = 0.8345-8.962° The fourth iteration will b 1 V 2,4 = 0.3603-146.3° -(1.9612/101.3°)(120°) 1.9612-78.8° 0.8345/+8.962 = 0.8320-8.962°
Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
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Can you help give a detailed step by step explanation of the math in this solution:
![This new estimate for V2 substituted back to the equation will produce the
second estimate:
V
2.2
1
=
0.3603-146.3°
-(1.9612/101.3°)(120°)
1.9612-78.8° 0.8797/+8.499°
=0.8412-8.499°
The third iteration will be
V
2.3
1
0.3603-146.3°
(1.9612/101.3°)(120°)]
1.9612-78.8° 0.8412/+8.499°
= 0.8345-8.962°
The fourth iteration will b
1
V
2,4
=
0.3603-146.3°
-(1.9612/101.3°)(120°)
1.9612-78.8° 0.8345/+8.962
= 0.8320-8.962°](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa88017a3-8c13-4545-a5d5-d0ca8fe0a450%2Fc89f7964-b546-4529-b395-5309fa8456c7%2F2s3vv7q_processed.png&w=3840&q=75)
Transcribed Image Text:This new estimate for V2 substituted back to the equation will produce the
second estimate:
V
2.2
1
=
0.3603-146.3°
-(1.9612/101.3°)(120°)
1.9612-78.8° 0.8797/+8.499°
=0.8412-8.499°
The third iteration will be
V
2.3
1
0.3603-146.3°
(1.9612/101.3°)(120°)]
1.9612-78.8° 0.8412/+8.499°
= 0.8345-8.962°
The fourth iteration will b
1
V
2,4
=
0.3603-146.3°
-(1.9612/101.3°)(120°)
1.9612-78.8° 0.8345/+8.962
= 0.8320-8.962°
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