Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below. The design of the studyjustifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct a 99% confidence interval estimate of o, thestandard deviation of the duration times of game play. Assume that this sample was obtained from a population with a nomal distribution.4,1074,0094,8215,0254,8244,7855,0413,8254,4074,9994,2924,182Click the icon to view the table of Chi-Square critical values.The confidence interval estimate is sec

to find variance valuestep 1: add them up4107+ 4009+ 4821 + 5025+ 4824 + 4785 + 5041 + 3825+ 4407 +…

Answered: Twelve different video games showing…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct a 98% confidence interval estimate of o, the standard deviation of the duration times of game play. Assume that this sample was obtained from a population with a normal distribution. 4,843 4,158 Click the icon to view the table of Chi-Square critical values. 4,861 4,480 4,630 4,751 4,310 4,261 4,244 3,822 The confidence interval estimate is sec<
Let m1 and m2 denote the true average ages (in years) of students at two different colleges. Assume both population distributions are normal with equal variances. Calculate and interpret a 99% confidence interval for m1 - m2 using the following data. Sample Sample Size Sample Mean variance College 1 10 25 College 2 9. 24 O 99% C.I. is (-2.49, 4.49). The samples suggest that the two colleges` students have significantly different ages. O 99% C.I. is (-2.10, -0.316). The samples do not suggest that the two colleges' students have significantly different ages. O 99% C.I. is (-2.10, -0.316). The samples suggest that the two colleges studen have significantly different ages. O 99% C.I. is (-2.49, 4.49). The samples do not suggest that the two colleges` students have significantly different ages.
10 squirrels were found to have an average weight of 610 grams with a sample standard deviation of 7.75 . Find the 95 % confidence interval of the true mean weight (assume the t-student distribution). A.)(608.25, 614.16) B.)(561.02, 614.16) C.) (604.46,615.54) D.) (513.79, 612.77)
3. A random sample of 12 graduates of a certain secretarial school typed an average of 79.3 words per minute with a standard deviation of 7.8 words per minute. Assuming a normal distribution for the number of words typed per minute, Find: a. 93% confidence interval for the average number of words typed by all graduates of this school.
Twelve different video games showing substance use were observed and the duration of times of game play (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct a 98 % confidence interval estimate of sigma , the standard deviation of the duration times of game play. Assume that this sample was obtained from a population with a normal distribution. 4 comma 808 4 comma 998 4 comma 457 4 comma 845 4 comma 900 4 comma 214 4 comma 584 4 comma 798 4 comma 935 4 comma 381 4 comma 464 4 comma 312 LOADING... Click the icon to view the table of Chi-Square critical values. The confidence interval estimate is nothing secless than sigmaless thannothing sec.
A study reported that finger rings increase the growth of bacteria on health-care workers’ hands. Research suggests that 31 percent of health-care workers who wear rings have bacteria on one or both hands. Suppose that independent random samples of 100 health-care workers wearing rings is selected. What is the standard deviation of the sampling distribution of the sample proportions of health-care workers having bacteria on one or both hands? A. 100 B. 0.0462 C. 0.69
random sample of 25 business students required an average of 50.7 minutes to complete a statistics exam. Assume that the population standard deviation to complete the exam was 10.4 minutes. The 99% confidence interval around this sample mean is
Assume that the heights of female executives are normally distributed. A random sample of 20 female executives have a mean height of 62.5 inches and a standard deviation of 1.8 inches. Construct a 98% confidence interval for the population variance, σ2
Twelve different video games showing substance use were observed and the duration of times of gameplay (in seconds) are listed below. The design of the study justifies the assumption that the sample can be treated as a simple random sample. Use the sample data to construct a 95%confidence interval estimate of σ, the standard deviation of the duration times of gameplay. Assume that this sample was obtained from a population with a normal distribution. 4,087 4,683 4,759 3,848 4,528 3,962 3,825 4,375 4,416 4,719 3,861 3,819
A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho H1 H2 H₁: H1 H2 The test statistic, t, is -1.55. (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) OB. Ho: H1 H2 H₁₁₂ D. Ho: H1 H2 H₁: H1 H2 Treatment Placebo μ H₁ H2 n 25 40 X 2.38 2.65 S 0.53 0.87
In a random sample of 38 criminals convicted of a certain crime, it was determined that the mean length of sentencing was 61 months, with a standard deviation of 8 months. Construct and interpret a 95% confidence interval for the mean length of sentencing for this crime. Select the correct choice below and fill in the answer boxes to complete your choice.(Use ascending order. Round to one decimal place as needed.) A. 95% of the sentences for the crime are between ____ and ____ months. B. There is a 95% probability that the mean length of sentencing for the crime is between ____ and ____ months. C. We can be 95% confident that the mean length of sentencing for the crime is between
Announcements for 83 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean length of the conferences was 3.96 days, with a standard deviation of 1.24 days. Assume the underlying population is normal. 1)In words define the random variables x and x̅ X is the mean length from a sample of 83 engineering conferences and x̅ is the length of an engineering conference. X is the length of an engineering conference and x̅ is the mean length from a sample of 83 engineering conferences. X is the number of engineering conferences and x̅ is the mean number of engineering conferences listed in IEEE spectrum magazine. X is the mean number of engineering conferences listed in IEEE spectrum magazine and x̅ is the number of engineering conferences. 2)Which distribution should you use for this problem? Explain your choice. The student’s t-distribution should be used because the sample mean is smaller than 30. The student’s t-distribution…

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