Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 8.73 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 19 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. Take Sample Number of students 19 Sample mean 6.818 Sample standard deviation 2.017 Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 99% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".

MATLAB: An Introduction with Applications
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(b) Based on your sample, graph the 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals.

- Enter the values for the lower and upper limits on the graph to show your confidence interval.
- For the point (♦), enter the claim 8.73 from the report.

Graph: 
- The 99% confidence interval is displayed as a horizontal line.
- The lower limit is marked at 0.000.
- The upper limit is marked at 10.000.
- A red diamond indicates the claim at 8.73 on the graph, but incorrectly positioned at 5.000 for instructional purposes.

(c) Does the 99% confidence interval you constructed contradict the claim made in the report?

Choose the best answer from the choices below.

- ○ No, the confidence interval does not contradict the claim. The mean of 8.73 hours from the report is inside the 99% confidence interval.
- ○ No, the confidence interval does not contradict the claim. The mean of 8.73 hours from the report is outside the 99% confidence interval.
- ○ Yes, the confidence interval contradicts the claim. The mean of 8.73 hours from the report is inside the 99% confidence interval.
- ○ Yes, the confidence interval contradicts the claim. The mean of 8.73 hours from the report is outside the 99% confidence interval.
Transcribed Image Text:(b) Based on your sample, graph the 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. - Enter the values for the lower and upper limits on the graph to show your confidence interval. - For the point (♦), enter the claim 8.73 from the report. Graph: - The 99% confidence interval is displayed as a horizontal line. - The lower limit is marked at 0.000. - The upper limit is marked at 10.000. - A red diamond indicates the claim at 8.73 on the graph, but incorrectly positioned at 5.000 for instructional purposes. (c) Does the 99% confidence interval you constructed contradict the claim made in the report? Choose the best answer from the choices below. - ○ No, the confidence interval does not contradict the claim. The mean of 8.73 hours from the report is inside the 99% confidence interval. - ○ No, the confidence interval does not contradict the claim. The mean of 8.73 hours from the report is outside the 99% confidence interval. - ○ Yes, the confidence interval contradicts the claim. The mean of 8.73 hours from the report is inside the 99% confidence interval. - ○ Yes, the confidence interval contradicts the claim. The mean of 8.73 hours from the report is outside the 99% confidence interval.
Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 8.73 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 19 college students and record the number of hours each slept the night before finals.

Follow the steps below to construct a 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.)

(a) Click on "Take Sample" to see the results for your random sample.

| Number of students | Sample mean | Sample standard deviation |
|--------------------|-------------|---------------------------|
| 19                 | 6.818       | 2.017                     |

Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 99% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute".

- **Sample size:** [ ]
- **Point estimate:** [ ]
- **Sample standard deviation:** [ ]
- **Critical value:** [ ]
- **Compute**

**Standard error:**  
**Margin of error:**  
**99% confidence interval:**

**Critical values table:**
- \( t_{0.005} = 2.878 \)
- \( t_{0.010} = 2.552 \)
- \( t_{0.025} = 2.101 \)
- \( t_{0.050} = 1.734 \)
- \( t_{0.100} = 1.330 \)
Transcribed Image Text:Suppose that the population of the number of hours slept by all college students the night before finals is approximately normally distributed. A report claimed that the mean of this population is 8.73 hours. As a student wellness advocate, you want to test this claim, so you select a random sample of 19 college students and record the number of hours each slept the night before finals. Follow the steps below to construct a 99% confidence interval for the population mean of all the numbers of hours slept by college students the night before finals. Then state whether the confidence interval you construct contradicts the report's claim. (If necessary, consult a list of formulas.) (a) Click on "Take Sample" to see the results for your random sample. | Number of students | Sample mean | Sample standard deviation | |--------------------|-------------|---------------------------| | 19 | 6.818 | 2.017 | Enter the values of the sample size, the point estimate of the mean, the sample standard deviation, and the critical value you need for your 99% confidence interval. (Choose the correct critical value from the table of critical values provided.) When you are done, select "Compute". - **Sample size:** [ ] - **Point estimate:** [ ] - **Sample standard deviation:** [ ] - **Critical value:** [ ] - **Compute** **Standard error:** **Margin of error:** **99% confidence interval:** **Critical values table:** - \( t_{0.005} = 2.878 \) - \( t_{0.010} = 2.552 \) - \( t_{0.025} = 2.101 \) - \( t_{0.050} = 1.734 \) - \( t_{0.100} = 1.330 \)
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