Tw_wmm IR Spectrum (liquid film) 4000 00 80 60 -40 20 % of base peak 3376 40 10 3000 59 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 73 200 1 9 80 DEPT CH₂ CH₂ CH ¹H NMR Spectrum (200 MHz, CDCI, solution) 1 8 M+= 88 (<1%) 2000 v (cm¹) 120 m/e 160 160 I 7 1600 1200 200 240 120 Mass Spectrum I 6 5 800 I C5H₁20 280 solvent 80 I 4 problem 78 3 No significant UV absorption above 220 nm 40 f 2 08 (ppm) 1 TMS 1 0 8 (ppm
Tw_wmm IR Spectrum (liquid film) 4000 00 80 60 -40 20 % of base peak 3376 40 10 3000 59 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 73 200 1 9 80 DEPT CH₂ CH₂ CH ¹H NMR Spectrum (200 MHz, CDCI, solution) 1 8 M+= 88 (<1%) 2000 v (cm¹) 120 m/e 160 160 I 7 1600 1200 200 240 120 Mass Spectrum I 6 5 800 I C5H₁20 280 solvent 80 I 4 problem 78 3 No significant UV absorption above 220 nm 40 f 2 08 (ppm) 1 TMS 1 0 8 (ppm
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:4000
100
80
60
20
% of base peak
3376
40
10
3000
59
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
173
proton decoupled
200
I
9
80
¹H NMR Spectrum
(200 MHz, CDCI, solution)
DEPT CH₂ CH₂ CH4
IR Spectrum
(liquid film)
2000
M+88 (<1%)
120
1600
v (cm¹)
m/e
160
160
I
I
8 7
mmm
1
120
200 240
6
1200
.
Mass Spectrum
L
800
1
5
C5H₁20
280
solvent
L
80
4
problem 78
3
No significant UV
absorption above 220 nm
40
Il
08 (ppm)
1
2
1
TMS
0
8 (ppm)
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