What is the IR and HNMRAndCNMR and mass in this example 10IR SpectumNow40003000714013C NMR Spectrum(500 M, COCI, solson)80DEPT Ci Ct CHproton decoupled200'H NMR Spectrum(200 MP CDC), solution)9En178812008001800V (em')Mass SpectrumC₂H14032000M* 158 (15)120100m/e160200 240 20061202.005solvent80expansion1.50 ppm43Problem 50No significant UVabsorption above 220 nm4008 (ppm)TMS08 (ppm)130

Answered: Image /qna-images/answer/25154fb8-ae37-42f6-9acd-ac922c5c17ca.jpg

IR Spectum Now 4000 3000 40 13C NMR Spectrum (500 M, COCI, soon) 80 2000 DEPT Ci ct cHt proton decoupled 200 H NMR Spectrum (200 MH, CDC), solution) En Tirss 1800 1200 000 Mass Spectrum C₂H₁403 M¹ - 168 (15) 120 100 V (em') 160 m/e 200 240 200 120 solvent 80 Problem 50 No significant UV absorption above 220 nm 40 08 (ppm)

IR Spectum Now 4000 3000 40 13C NMR Spectrum (500 M, COCI, soon) 80 2000 DEPT Ci ct cHt proton decoupled 200 H NMR Spectrum (200 MH, CDC), solution) En Tirss 1800 1200 000 Mass Spectrum C₂H₁403 M¹ - 168 (15) 120 100 V (em') 160 m/e 200 240 200 120 solvent 80 Problem 50 No significant UV absorption above 220 nm 40 08 (ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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