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Try to rationalize the sign of A,S°. O The answer is positive, which is consistent with water production that will soon become a liquid. O The answer is positive, which is consistent with higher atomic weight of nitrogen in comparison with hydrogen and its higher mobility. O The answer is positive, which is consistent with 1 mole of a complex gas and 4 moles of a simple gas going to 1 mole of simple gas and 4 moles of a complex gas. Submit Request Answer

Try to rationalize the sign of A,S°. O The answer is positive, which is consistent with water production that will soon become a liquid. O The answer is positive, which is consistent with higher atomic weight of nitrogen in comparison with hydrogen and its higher mobility. O The answer is positive, which is consistent with 1 mole of a complex gas and 4 moles of a simple gas going to 1 mole of simple gas and 4 moles of a complex gas. Submit Request Answer

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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please help me with part b,d,f,h as they are all part of one question. I really want to make sure i get them right. I will highly consider giving thumbs up 

Part E KC103 (s) + 02 (9) → KCI04 (s) Express your answer using one decimal place. A,S° = -94.7 JK-1 mol-! Submit Previous Answers Correct Part F Try to rationalize the sign of A, S°. O The answer is negative, which is consistent with a higher activity of O2. O The answer is negative, which is consistent with loser activity of KC1O4 (s). O The answer negative, which is consistent with a decrease in the number of moles of gas. Submit Request Answer Part G N204 (g) + 4 H2 (g) → N2 (9) + 4 H2O (g) Express your answer using one decimal place. A,S° = 119.6 JK-' mol-! Submit Previous Answers v Correct Part H Try to rationalize the sign of A,S°. O The answer positive, which is consistent with water production that will soon become a liquid. O The answer is positive, which is consistent with higher atomic weight of nitrogen in comparison with hydrogen and its higher mobility. O The answer is positive, which is consistent with 1 mole of a complex gas and 4 moles of a simple gas going to 1 mole of simple gas and 4 moles of a complex gas. Submit Request Answer
Transcribed Image Text:Part E KC103 (s) + 02 (9) → KCI04 (s) Express your answer using one decimal place. A,S° = -94.7 JK-1 mol-! Submit Previous Answers Correct Part F Try to rationalize the sign of A, S°. O The answer is negative, which is consistent with a higher activity of O2. O The answer is negative, which is consistent with loser activity of KC1O4 (s). O The answer negative, which is consistent with a decrease in the number of moles of gas. Submit Request Answer Part G N204 (g) + 4 H2 (g) → N2 (9) + 4 H2O (g) Express your answer using one decimal place. A,S° = 119.6 JK-' mol-! Submit Previous Answers v Correct Part H Try to rationalize the sign of A,S°. O The answer positive, which is consistent with water production that will soon become a liquid. O The answer is positive, which is consistent with higher atomic weight of nitrogen in comparison with hydrogen and its higher mobility. O The answer is positive, which is consistent with 1 mole of a complex gas and 4 moles of a simple gas going to 1 mole of simple gas and 4 moles of a complex gas. Submit Request Answer
Part A Use data given below to calculate A, S° for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25° C Substance A,S°,JK-l mol-1 4 NO2 (g) + 2 H2O (1) + O2(9) → 4 HNO3 (ag) Cr (s) 23.8 Express your answer using one decimal place. Cr2 O3 (s) |CO (g) CO2 (g) 81.2 A,S° = -721.6 JK-' mol-1 197.7 213.8 Submit Previous Answers H2 (9) H20 (g) 130.7 188.8 Correct H2O (1) 70.0 HNO3 (aq) 146.0 Part B N2 (9) N204 (9) NO (g) 191.6 304.4 Try to rationalize the sign of A; S°. 210.8 The answer is negative, which is consistent with a decrease in the number of moles of gas. NO2 (g) 02 (g) 240.1 205.2 O The answer is negative, which is consistent with an ionic compound HNO3 formed in the reaction. KC103 (s) 143.1 O The answer is negative, which is consistent with a decrease in the number of moles of gas. KC104 (s) 151.0 O The answer is negative, which is consistent with an increase in the number of moles of liquid components. Submit Request Answer Part C СrzO3(s) + 3 СО (9) —— 2 Сr (s) + з СО2 (9) Express your answer using one decimal place. A,S° = 14.7 JK-1 mol-1 Submit Previous Answers v Correct Part D Try to rationalize the sign of A,S°. O The change is small and positive because the number of moles of compounds increases. O The change is small because the number of moles of gas is constant. O The change is small because Cr2 O3 is more active then metalic Cr. Submit Request Answer
Transcribed Image Text:Part A Use data given below to calculate A, S° for each of the reactions. Standard Thermodynamic Quantities for Selected Substances at 25° C Substance A,S°,JK-l mol-1 4 NO2 (g) + 2 H2O (1) + O2(9) → 4 HNO3 (ag) Cr (s) 23.8 Express your answer using one decimal place. Cr2 O3 (s) |CO (g) CO2 (g) 81.2 A,S° = -721.6 JK-' mol-1 197.7 213.8 Submit Previous Answers H2 (9) H20 (g) 130.7 188.8 Correct H2O (1) 70.0 HNO3 (aq) 146.0 Part B N2 (9) N204 (9) NO (g) 191.6 304.4 Try to rationalize the sign of A; S°. 210.8 The answer is negative, which is consistent with a decrease in the number of moles of gas. NO2 (g) 02 (g) 240.1 205.2 O The answer is negative, which is consistent with an ionic compound HNO3 formed in the reaction. KC103 (s) 143.1 O The answer is negative, which is consistent with a decrease in the number of moles of gas. KC104 (s) 151.0 O The answer is negative, which is consistent with an increase in the number of moles of liquid components. Submit Request Answer Part C СrzO3(s) + 3 СО (9) —— 2 Сr (s) + з СО2 (9) Express your answer using one decimal place. A,S° = 14.7 JK-1 mol-1 Submit Previous Answers v Correct Part D Try to rationalize the sign of A,S°. O The change is small and positive because the number of moles of compounds increases. O The change is small because the number of moles of gas is constant. O The change is small because Cr2 O3 is more active then metalic Cr. Submit Request Answer
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