Try This 8.3.2 wish to estimate, with 90% confidence, the population proportion of U.S. adults who are onfident in the stability of the U.S. banking system. Your estimate must be accurate within 3% of the population proportion. Find the minimum sample size needed, using a prior study that found that 43% of U.S. adults are confident in the stability of the U.S. banking system.

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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her. If the candi
needed? Because the p-hat is not
A
E = 0.07
c = 0.90
Solution
Given information:
Z. = 1.645
At c = 0.90 ,
n = pq () = 0.5(1 – 0.5) (4)
2
Minimum Sample Size to Estimate p :
0.07
139 (rounded up)
Try This 8.3.2
wich to estimate, with 90% confidence, the population proportion of U.S. adults who are
onfident in the stability of the U.S. banking system. Your estimate must be accurate within 3% of the
nopulation proportion. Find the minimum sample size needed, using a prior study that found that
43% of U.S. adults are confident in the stability of the U.S. banking system.
Confidence Interval Summary
Mean with Standard
Mean with Standard
Proportions
Deviation o Known
Deviation o Unknown
Critical Value
Zc
tc with d.f.=n – 1
E = tc n
Margin of Error
S
E = Zc Jn
E = Zc
的一”
Transcribed Image Text:her. If the candi needed? Because the p-hat is not A E = 0.07 c = 0.90 Solution Given information: Z. = 1.645 At c = 0.90 , n = pq () = 0.5(1 – 0.5) (4) 2 Minimum Sample Size to Estimate p : 0.07 139 (rounded up) Try This 8.3.2 wich to estimate, with 90% confidence, the population proportion of U.S. adults who are onfident in the stability of the U.S. banking system. Your estimate must be accurate within 3% of the nopulation proportion. Find the minimum sample size needed, using a prior study that found that 43% of U.S. adults are confident in the stability of the U.S. banking system. Confidence Interval Summary Mean with Standard Mean with Standard Proportions Deviation o Known Deviation o Unknown Critical Value Zc tc with d.f.=n – 1 E = tc n Margin of Error S E = Zc Jn E = Zc 的一”
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