The owner of the west end Kwick fill gas station wishes to determine the proportion of customers who pay at the pump using credit card or debit card. He surveys 100 customers and finds that 85 pay at the pump. (Round your answers to 3 decimal places.) a. Estimate the value of the population proportion: b. Develop a 95% confidence interval for the population proportion.
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A: From the provided information, Sample size (n) = 902 Out of which 507 said yes that is x = 507
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
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A: Given information n = 970 x = 555
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
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Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: Given, The objective is to find the best point estimate and the margin of error.
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A: X=536, n=1099
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A: n=910X=502
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A: Margin of error for proportion is given by, MOE= z*√pq/n Where P Is proportion and Q= 1-P n is…
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A:
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: Answer:
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: Given that A research institute poll asked respondents if they felt vulnerable to identity theft.…
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: A research institute poll asked respondents if they felt vulnerable to identity theft. In the…
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A: Given, Confidence level, C = 95% = 0.95So, level of significance, α = 1-0.95 = 0.05Margin of error,…
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A: Given Information: Sample Size, n =222Sample Proportion, p^=28% =0.28 To find out the margin of…
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: Solution: a. From the given information, X=580 and n=923.
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: We have given that, n=916, x=544 α= 1- confidence level = 0.05 Therefore critical value Zα/2 =1.96
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Q: b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.)
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A: given that,possible chances (x)=529size(n)=1016success rate ( p )= x/n = 0.5207(a)point of estimate…
Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…
A: Thank you for posting the question. As your question has more than 3 parts, as per the policy, we…
The owner of the west end Kwick fill gas station wishes to determine the proportion of customers who pay at the pump using credit card or debit card. He surveys 100 customers and finds that 85 pay at the pump. (Round your answers to 3 decimal places.)
a. Estimate the value of the population proportion:
b. Develop a 95% confidence interval for the population proportion.
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- Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1059 and x= 551 who said "yes." Use a 90% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 994 and x = 565 who said "yes." Use a 99% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1064 and x = 559 who said "yes." Use a 90% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. 0.525 (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= □ (Round to three decimal places as needed.)A poll of 2368 U.S. adults found that 40% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 90% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 95% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to % The more error we allow, the less precise our estimate. Therefore, as the confidence level increases, the precision of our…Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 993 and x = 566 who said "yes." Use a 99% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=979 and x = 572 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E=0 (Round to three decimal places as needed.) c) Construct the confidence interval. (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. C O A. One has 95% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion. OB. 95% of sample proportions will fall between the lower bound and the upper bound. OC. One has 95% confidence that the sample proportion is equal to the…A poll of 2338 U.S. adults found that 71% regularly used Facebook as a news source. Find the margin of error and confidence interval for the percentage of U.S. adults who regularly use Facebook as a news source, at the 99% level of confidence. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to %Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1072 and x = 595 who said "yes." Use a 95% confidence level. E Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed. b) Identify the value of the margin of error E E= (Round to three decimal places as needed.) c) Construct the confidence interval. (Round to three decimal places as needed. ) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. O A. There is a 95% chance that the true value of the population proportion will fall between the lower bound and the upper bound. O B. 95% of sample proportions will fall between the lower bound and the upper bound. O C. One has 95% confidence that the sample proportion is equal to the population proportion. O D.…Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1045 and x = 543 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval. OA new fertilizer was applied to the soil of 246 bean plants. 25% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage):Confidence Interval: % to %Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 969 and x = 545 who said "yes." Use a 90% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.) c) Construct the confidence interval.Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=914 and x = 556 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. 0.608 (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E= (Round to three decimal places as needed.)SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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