The British Department of Transportation studied to see if people avoid driving on Friday the 13th. They did a traffic count on a Friday and then again on a Friday the 13th at the same two locations. The data for each location on the two different dates is in the table. Do the data show that on average fewer people drive on Friday the 13th? Test at the 5% level. Traffic Count 6th 13th 1990, July 137669 135825 1990, July 129699 128891 1991, September 136898 138275 1991, September 138966 139940 1991, December 132021 129640 1991, December 119268 119214 1992, March 131938 131104 1992, March 123306 124760 1992, November 129499 129219 1992, November 138568 135934 Dates State the null and alternative hypotheses. Ho: Hd? Ha: Hd ? ✓ Calculate the test statistic. Round to four decimal places. d = Calculate the standardized test statistic. Round three decimal places. t = Find the p-value. Round to four decimal places. n value

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The British Department of Transportation studied to see if people avoid driving
on Friday the 13th. They did a traffic count on a Friday and then again on a
Friday the 13th at the same two locations. The data for each location on the
two different dates is in the table. Do the data show that on average fewer
people drive on Friday the 13th? Test at the 5% level.
Traffic Count
6th
13th
1990, July
137669
135825
1990, July
129699
128891
1991, September
136898
138275
1991, September
138966
139940
1991, December 132021 129640
1991, December
119268
119214
1992, March
131938
131104
1992, March
123306
124760
1992, November
129499 129219
1992, November 138568 135934
Dates
State the null and alternative hypotheses.
Ho: Ha?
Ha: Hd ? ✓
Calculate the test statistic. Round to four decimal places.
d =
Calculate the standardized test statistic. Round three decimal places.
t =
Find the p-value. Round to four decimal places.
p-value
Transcribed Image Text:The British Department of Transportation studied to see if people avoid driving on Friday the 13th. They did a traffic count on a Friday and then again on a Friday the 13th at the same two locations. The data for each location on the two different dates is in the table. Do the data show that on average fewer people drive on Friday the 13th? Test at the 5% level. Traffic Count 6th 13th 1990, July 137669 135825 1990, July 129699 128891 1991, September 136898 138275 1991, September 138966 139940 1991, December 132021 129640 1991, December 119268 119214 1992, March 131938 131104 1992, March 123306 124760 1992, November 129499 129219 1992, November 138568 135934 Dates State the null and alternative hypotheses. Ho: Ha? Ha: Hd ? ✓ Calculate the test statistic. Round to four decimal places. d = Calculate the standardized test statistic. Round three decimal places. t = Find the p-value. Round to four decimal places. p-value
Find the p-value. Round to four decimal places.
p-value
=
State your decision.
O Since the p-value is greater than .05, fail to reject Ho.
Since the p-value is less than .05, reject Ho.
Since the p-value is greater than .05, reject Ho.
O Since the p-value is less than .05, fail to reject Ho.
Interpret the results.
O At the 5% level of significance, there is enough evidence to show that on
average more people drive on Friday the 13th.
At the 5% level of significance, there is not enough evidence to show
that on average a different number of people drive on Friday the 13th.
At the 5% level of significance, there is not enough evidence to show
that on average fewer people drive on Friday the 13th.
At the 5% level of significance, there is enough evidence to show that on
average fewer people drive on Friday the 13th.
At the 5% level of significance, there is not enough evidence to show
that on average more people drive on Friday the 13th.
O At the 5% level of significance, there is enough evidence to show that on
average a different number of people drive on Friday the 13th.
Transcribed Image Text:Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is greater than .05, fail to reject Ho. Since the p-value is less than .05, reject Ho. Since the p-value is greater than .05, reject Ho. O Since the p-value is less than .05, fail to reject Ho. Interpret the results. O At the 5% level of significance, there is enough evidence to show that on average more people drive on Friday the 13th. At the 5% level of significance, there is not enough evidence to show that on average a different number of people drive on Friday the 13th. At the 5% level of significance, there is not enough evidence to show that on average fewer people drive on Friday the 13th. At the 5% level of significance, there is enough evidence to show that on average fewer people drive on Friday the 13th. At the 5% level of significance, there is not enough evidence to show that on average more people drive on Friday the 13th. O At the 5% level of significance, there is enough evidence to show that on average a different number of people drive on Friday the 13th.
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