True or False? Researchers are assessing the effects of ambient noise level and plant location on worker productivity by a two-factor ANOVA without replication, at . The results are summarized below. By comparing the F statistic for plant location with the F critical value, we reject the null hypothesis that plant location has no effect on the worker productivity. Select one: True

True or False? Researchers are assessing the effects of ambient noise level and plant location on worker productivity by a two-factor ANOVA without replication, at . The results are summarized below. By comparing the F statistic for plant location with the F critical value, we reject the null hypothesis that plant location has no effect on the worker productivity. Select one: True

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Table 3: Significant Influence between Management Capability of Administrators and Productivity of Employees Leadership Skills Productivity of Employees Beta t-value p-value Skills .624** 1.56 .000 Knowledge .456** 4.25 .000 Aptitudes .552** 4.22 .000 R2 =.639 Evalue=6.45 p value=.000 Present, analyze and interpret the data. Make inference at the end of your discussion
The manager of a political party wants to find out the association between the campaign spending (Large, medium and small) and the vote obtained (Majority, Average and minority). Use Chi-squared hypothesis test for association to test that there is an association between the variable in campaign spending and the variable in vote obtained with five percent level of significance. The manager uses MS excel to calculate the Chi-squared stat value and the result is 8.874. Critical value: At 1% = 13.277 :At 5% = 9.488 :At 10% = 7.779 1. State the decision rule 2. Conclusion and decision 3. State the alternative hypothesis and the null hypothesis
Question 6 A one-way within-groups ANOVA on 2 and 15 degrees of freedom results in an F statistic of 3.12. What decision should be made about the hypothesis based on this statistic? Reject the null hypothesis and conclude the independent variable has no effect. Fail to reject the null hypothesis because the Fstatistic does not exceed the critical cutoff. Fail to reject the null hypothesis and conclude there is no effect of the independent variable. Reject the null hypothesis and conclude there are differences among the levels of the independent variable.
Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on arganisms, an expert claimed that the amount of gamma radiation needed to sterilize a colany of tardigrades no longer has a mean of 1200 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy.) A study was conducted on a sample of 21 randomly selected tardigrade colonies, finding that the amount of gamma radiation needed to sterilize a colony had a sample mean af 1225 Gy, with a sample standard deviation of 65 Gy. Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level af significance, to support the claim that H, the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is nat equal to 1200 Gy. (a) State the null hypothesis and the…
In a research setting, the efficiency of homecare workers (part-time and full-time) were compared. Data is given below. Is there a difference between full-time and part-time homecare workers? (Variances are assumed to be homogenous, α=0.05). Group Efficiency Points Group Efficiency Points Full-time 5 Part-time 1 Full-time 3 Part-time 3 Full-time 4 Part-time 4 Full-time 1 Part-time 4 Full-time 2 Part-time 2 Full-time 3 Part-time 0 Full-time 2
A researcher wanted to examine whether type of dog food (freeze dried meat vs generic brand kibble) would affect dogs’ attention span. The researcher hypothesized that dogs who ate freeze dried meat would have longer attention spans than those who ate generic brand kibble. The researcher used a single sample of 13 subjects, that took part in both treatment conditions. The researcher set the alpha level at .01. The mean of the difference scores (MD)was 7.0 and the SSD for the difference in attention spans was 144. What is the calculated test statistic to the nearest thousandth? Be sure to put the positive or negative sign in front of it. Note: SHOW ALL WORK!!! Based on your work above, do you reject or retain the null? reject retain Based on your conclusion regarding the null, was there a treatment effect? Yes No
Productivity is the key driver of wages and one of the most importantdeterminants of living standards. The British Chambers of Commercecommissioned research into understanding whether labour productivity in theautomotive manufacturing sector in England and Ireland were the same ordifferent. The researchers collected data on a random sample of 8 firms inEngland and 4 in Ireland and recorded productivity in units of value added (£)per hour. It is assumed that firm-level productivity has a normal distribution.The following data were collected:Ireland 47 56 43 68England 39 50 39 45 50 43 35 43(i) Set up appropriate null and alternative hypotheses and conduct a test ofthe hypotheses of equal mean productivity in Ireland and England at 5 percent significance level under the assumption of unknown but equalpopulation variances. Provide as much detail as possible on yourprocedures. Clearly show all your steps in testing and state your decision.Discuss the economic implications of your findings.…
Is the proportion of wildfires caused by humans in the south lower than the proportion of wildfires caused by humans in the west? 360 of the 501 randomly selected wildfires looked at in the south were caused by humans while 435 of the 588 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.10 level of significance? For this study, we should use Select an answer t-test for the difference between two dependent population means z-test for the difference between two population proportions t-test for a population mean t-test for the difference between two independent population means z-test for a population proportion The null and alternative hypotheses would be: Select an answer μ1 p1 Select an answer < ≠ > = Select an answer μ2 p2 (please enter a decimal) Select an answer μ1 p1 Select an answer > ≠ < = Select an answer p2 μ2 (Please enter a decimal) The test statistic ? z t = (please show your…
A new method was developed to reduce variability of test scores by eliminating lower scores. Two groups, one called the control group and the other, the experimental group, both took the same test. The experimental group was taught using the new method. Do the data provide sufficient evidence to conclude that there is less variation among scores when the new method is used? Perform an F-test at the 1% significance level. (Note: s, = 6.3 and Control Experimental 30 19 29 26 33 36 29 18 33 31 S2 = 3.3.) 33 18 19 32 27 32 29 30 33 ... .. First find the null and alternative hypotheses. Which of the following correctly states the hypotheses? O A. Ho: 01 72 Ha: 01 = 02 O B. Ho: 01 >02 Ha: 0102 Ha: 01 #02 O E. Ho: 01 =02 Ha: 01 02 nts SCO Compute the test statistic F. Scor (Round to three decimal places as needed.) ess
10.20 In a random sample of recent high school graduates, two characteristics were recorded (the average score and the number of correct answers for the SAT test). This information was classified as shown in Table 10.8. Is there a dependence between the number of correct answers on the SAT test and the average rankings statistically discernible at a level α = 0.01?
An engineer has designed a valve that will regulate water pressure on an automobile engine. The valve was tested on 250 engines and the mean pressure was 6.8pounds/square inch (psi). Assume the population variance is 0.810.81. If the valve was designed to produce a mean pressure of 6.7 psi, is there sufficient evidence at the 0.1 level that the valve performs above the specifications? Step 1 of 6: State the null and alternative hypotheses. Step 2 of 6: Find the value of the test statistic. Round your answer to two decimal places. Step 3 of 6: Specify if the test is one-tailed or two-tailed. Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal places. Step 5 of 6: Identify the level of significance for the hypothesis test. Step 6 of 6: Make the decision to reject or fail to reject the null hypothesis.
atients suffering from rheumatic diseases or osteoporosis often suffer critical losses in bone mineral density (BMD). Alendronate is one medication prescribed to build or prevent further loss of BMD. Holcomb and Rothenberg (A-3) looked at 96 women taking alendronate to determine if a difference existed in the mean percent change in BMD among five different primary diagnosis classifications. Group 1 patients were diagnosed with rheumatoid arthritis (RA). Group 2 patients were a mixed collection of patients with diseases including lupus, Wegener’s granulomatosis and polyarteritis, and other vasculitic diseases (LUPUS). Group 3 patients had polymyalgia rheumatica or temporal arthritis (PMRTA). Group 4 patients had osteoarthritis (OA) and group 5 patients had osteoporosis (O) with no other rheumatic diseases identified in the medical record. Changes in BMD are shown in the following table. Discuss the Alendronate medication data in terms of variability. To determine if a difference…