**Transcription and Explanation for Educational Website**---**Torque Experiment Data Table**This data table is part of an experiment that involves measuring and comparing torque values. The table is structured to record expected and measured torque values, alongside the percentage error for each trial.| Trial | Short Side Torque (Nm) "Expected Value" | Total Long Side Torque (Nm) "Measured Value" | % Error ||-------|-----------------------------------------|--------------------------------------------|---------|| Trial 1 | | | || Trial 2 | (same as above) | | || Trial 3 | (same as above) | | |**Explanation:**- **Short Side Torque (Nm):** Represents the expected torque on the short side, measured in Newton-meters (Nm).- **Total Long Side Torque (Nm):** Represents the measured torque on the long side, also in Newton-meters (Nm).- **% Error:** This column is reserved for calculating the percentage error, which is derived from comparing the expected and measured values for each trial.**Note:**- The table currently does not include specific numerical values but provides a framework for data collection and analysis.- The phrase "(same as above)" indicates that the expected torque value is consistent across all trials.This data collection method is crucial for understanding the accuracy and reliability of torque measurements in practical experiments. **Lab 10: Torque and Equilibrium Assignment****Position of the new pivot: 30.00 cm**| Position of the new pivot: 30.00 cm | mass | weight (N) | position | lever arm (m) | torque (Nm) ||-------------------------------------|----------------------|-----------------|--------------|-----------------------------|----------------------|| short side (all trials) | 20.74 g + 200 g = | _________ kg | 15.00 cm | 30.00 - 15.00 cm = ______ m | || long side (trial 1) | 20.90 g + 100 g = | _________ kg | 45.50 cm | 45.50 - 30.00 cm = ______ m | || long side (trial 2) | 20.90 g + 30 g = | _________ kg | 66.90 cm | 66.90 - 30.00 cm = ______ m | || long side (trial 3) | 20.90 g + 10 g = | _________ kg | 90.75 cm | 90.75 - 30.00 cm = ______ m | || meter stick center of mass (all trials) | 70.58 g = | _________ kg | 50.20 cm | 50.20 - 30.00 cm = ______ m | |### Explanation:This table is part of an educational lab assignment focused on understanding torque and equilibrium. It involves a series of trials to assess the torque exerted by weights placed at different lengths on a lever.- **Mass (g & kg):** The mass of the objects used in each trial, given in grams and converted to kilograms for calculations. - **Weight (N):** The weight in Newtons, derived from the mass. (Note: Actual calculation fields for weight are to be filled by students using the formula $ Weight = Mass \times g $, where $ g = 9.81 \, \text{m/s}^2 $.) - **Position (cm):** Location on the meter stick where each mass is placed, measured in centimeters from the pivot. - **Lever Arm (m):** The distance from the

Introduction: When a force is applied at a distance from the pivot axis with condition that force is…

Answered: trial 1 trial 2 trial 3 short side…

trial 1 trial 2 trial 3 short side torque (Nm) "expected value" (same as above) (same as above) total long side torque (Nm) "measured value" % error

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Chapter 10 learning guidelines
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