58.1%ResourcesLx Give Up?FeedbackA merry-go-round is spinning at a rate of 4.0 revolutions per minute. Cora is sitting 0.5 m from the center of the merry-go-round and Cameron is sitting right on the edge, 2.0 m from the center.What is the relationship between the rotational speeds of the two children?Cameron's rotational speed is four times as much as Cora's rotational speed.Cora's rotational speed is four times as much as Cameron's rotational speed.Cora's rotational speed is the same as Cameron's rotational speed.Cora's rotational speed is double Cameron's rotational speed.Cameron's rotational speed is double Cora's rotational speed.IncorrectWhat is the relationship between the tangential speeds of the two children?Cora's tangential speed is the same as Cameron's tangential speed.Cameron's tangential speed is double Cora's tangential speed.privacy policyterms of usehelpcontact usabout uscareers 58.1%ResourcesEx Give Up?FeedbackCameron's rotational speed is four times as much as Cora's rotational speed.Cora's rotational speed is four times as much as Cameron's rotational speed.Cora's rotational speed is the same as Cameron's rotational speed.Cora's rotational speed is double Cameron's rotational speed.Cameron's rotational speed is double Cora's rotational speed.IncorrectWhat is the relationship between the tangential speeds of the two children?Cora's tangential speed is the same as Cameron's tangential speed.Cameron's tangential speed is double Cora's tangential speed.Cora's tangential speed is double Cameron's tangential speed.Cora's tangential speed is four times as much as Cameron's rotational speed.Cameron's tangential speed is four times Cora's tangential speed.Incorrect1 privacy policy terms of usehelpcontact usabout uscareersO O O

1) rotational speed of the two children are equal because both of them are sitting on the same merry go round and revolving around a common central point. Thus correct answer is " cora's rotational speed is same as Cameron's rotational speed"Now, since rotational speed (w) is same for both of them , Therefore , V/R = v /r where V is the tangential speed of cora R is the distance of cora from central axis where v is the tangential speed of cameron r is the distance of cameron from central axis V/0.5 = v/2 4 V = v Therefore, Cameron's tangential speed is four times Cora's tangential speed

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Physics

A merry-go-round is spinning at a rate of 4.0 revolutions per minute. Cora is sitting 0.5 m from the center of the merry-go- round and Cameron is sitting right on the edge, 2.0 m from the center. What is the relationship between the rotational speeds of the two children? Cameron's rotational speed is four times as much as Cora's rotational speed. Cora's rotational speed is four times as much as Cameron's rotational speed. Cora's rotational speed is the same as Cameron's rotational speed. Cora's rotational speed is double Cameron's rotational speed. Cameron's rotational speed is double Cora's rotational speed. Incorrect What is the relationship between the tangential speeds of the two children? Cora's tangential speed is the same as Cameron's tangential speed. Cameron's tangential speed is double Cora's tangential speed.

A merry-go-round is spinning at a rate of 4.0 revolutions per minute. Cora is sitting 0.5 m from the center of the merry-go- round and Cameron is sitting right on the edge, 2.0 m from the center. What is the relationship between the rotational speeds of the two children? Cameron's rotational speed is four times as much as Cora's rotational speed. Cora's rotational speed is four times as much as Cameron's rotational speed. Cora's rotational speed is the same as Cameron's rotational speed. Cora's rotational speed is double Cameron's rotational speed. Cameron's rotational speed is double Cora's rotational speed. Incorrect What is the relationship between the tangential speeds of the two children? Cora's tangential speed is the same as Cameron's tangential speed. Cameron's tangential speed is double Cora's tangential speed.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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