Problems 10-16 Information: Jose' pushes a wheelbarrow consisting of a wheel (mass mw = 3 kg, radius r = 0.1 m) and a barrow body (mass mg = 30 kg). He accelerates from rest (state 1) to a velocity of 2 m/s (state 2), when he trips and lets the wheelchair roll down the hill (height h=2 m, 30 deg angle) to the bottom (state 3), where it hits a crate (mass mc = 20 kg) into motion (state 4). The ground has a friction coefficient of 0.5. Between states 1 and 2, when Jose' is balancing the wheelbarrow, all the weight is on the wheel. After that, the support spike drags along the ground, holding half the total weight, while the other half is on the wheel. 2

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Could you answer questions 15 and 16?

**Physics Problem Set**

**Question 15**

*Redacted Student Name*

If the collision between the wheelbarrow and the crate has a coefficient of restitution e = 0.6, how fast (m/s) does the crate move just after impact? Answer using three significant figures.
\[ \boxed{} \]

**Question 16**

*Redacted Student Name*

If the wheelbarrow were heavier but Jose' can still fully accelerate it, how would this affect its kinetic energy? The friction force from the ground? The post-collision speed of the crate? Express your answer as \( (KE, F, v) \)

- ⃝ (decrease, decrease, decrease)
- ⃝ (no change, no change, no change)
- ⃝ (increase, no change, decrease)
- ⃝ (increase, increase, increase)
- ⃝ (increase, decrease, decrease)

In these questions, you need to consider how changes in mass, acceleration capacity, and collision parameters such as the coefficient of restitution influence the kinetic energy (\( KE \)), friction force from the ground (\( F \)), and the post-collision speed (\( v \)) of the involved object.
Transcribed Image Text:**Physics Problem Set** **Question 15** *Redacted Student Name* If the collision between the wheelbarrow and the crate has a coefficient of restitution e = 0.6, how fast (m/s) does the crate move just after impact? Answer using three significant figures. \[ \boxed{} \] **Question 16** *Redacted Student Name* If the wheelbarrow were heavier but Jose' can still fully accelerate it, how would this affect its kinetic energy? The friction force from the ground? The post-collision speed of the crate? Express your answer as \( (KE, F, v) \) - ⃝ (decrease, decrease, decrease) - ⃝ (no change, no change, no change) - ⃝ (increase, no change, decrease) - ⃝ (increase, increase, increase) - ⃝ (increase, decrease, decrease) In these questions, you need to consider how changes in mass, acceleration capacity, and collision parameters such as the coefficient of restitution influence the kinetic energy (\( KE \)), friction force from the ground (\( F \)), and the post-collision speed (\( v \)) of the involved object.
### Problem Description

Jose' pushes a wheelbarrow consisting of a wheel (mass \( m_w = 3 \, \text{kg} \), radius \( r = 0.1 \, \text{m} \)) and a barrow body (mass \( m_g = 30 \, \text{kg} \)). He accelerates from rest (state 1) to a velocity of \( 2 \, \text{m/s} \) (state 2), when he trips and lets the wheelbarrow roll down the hill (height \( h = 2 \, \text{m} \), 30-degree angle) to the bottom (state 3), where it hits a crate (mass \( m_c = 20 \, \text{kg} \)) into motion (state 4). The ground has a friction coefficient of 0.5. Between states 1 and 2, when Jose' is balancing the wheelbarrow, all the weight is on the wheel. After that, the support spike drags along the ground, holding half the total weight, while the other half is on the wheel.

### Diagram Explanation

The diagram consists of four states:

1. **State 1: Jose' pushing the wheelbarrow**
   - Jose' is shown pushing the wheelbarrow from rest up a hill.

2. **State 2: Wheelbarrow in motion**
   - The wheelbarrow has accelerated to a velocity of \( 2 \, \text{m/s} \).

3. **State 3: Wheelbarrow rolling down the hill**
   - The wheelbarrow is shown rolling down a hill with a 30-degree incline and a height of \( h = 2 \, \text{m} \).

4. **State 4: Wheelbarrow hitting the crate**
   - At the bottom of the hill, the wheelbarrow strikes a crate, transferring some of its momentum.

### Question
What is conserved from state 1 to state 4? Select all that apply.

- Energy
- Mass
- Momentum
- Velocity

### Solution
The only fundamental physical quantity that is universally conserved in a closed system, regardless of the particular interactions (assuming no mass loss or gain), is **mass**. Therefore, the correct answer is:

- [x] Mass

This problem highlights fundamental physics concepts such as conservation of mass,
Transcribed Image Text:### Problem Description Jose' pushes a wheelbarrow consisting of a wheel (mass \( m_w = 3 \, \text{kg} \), radius \( r = 0.1 \, \text{m} \)) and a barrow body (mass \( m_g = 30 \, \text{kg} \)). He accelerates from rest (state 1) to a velocity of \( 2 \, \text{m/s} \) (state 2), when he trips and lets the wheelbarrow roll down the hill (height \( h = 2 \, \text{m} \), 30-degree angle) to the bottom (state 3), where it hits a crate (mass \( m_c = 20 \, \text{kg} \)) into motion (state 4). The ground has a friction coefficient of 0.5. Between states 1 and 2, when Jose' is balancing the wheelbarrow, all the weight is on the wheel. After that, the support spike drags along the ground, holding half the total weight, while the other half is on the wheel. ### Diagram Explanation The diagram consists of four states: 1. **State 1: Jose' pushing the wheelbarrow** - Jose' is shown pushing the wheelbarrow from rest up a hill. 2. **State 2: Wheelbarrow in motion** - The wheelbarrow has accelerated to a velocity of \( 2 \, \text{m/s} \). 3. **State 3: Wheelbarrow rolling down the hill** - The wheelbarrow is shown rolling down a hill with a 30-degree incline and a height of \( h = 2 \, \text{m} \). 4. **State 4: Wheelbarrow hitting the crate** - At the bottom of the hill, the wheelbarrow strikes a crate, transferring some of its momentum. ### Question What is conserved from state 1 to state 4? Select all that apply. - Energy - Mass - Momentum - Velocity ### Solution The only fundamental physical quantity that is universally conserved in a closed system, regardless of the particular interactions (assuming no mass loss or gain), is **mass**. Therefore, the correct answer is: - [x] Mass This problem highlights fundamental physics concepts such as conservation of mass,
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