Translate the following C program into NASM. #include int main() { int x = 0; char sent[20]; printf("Enter sentence: "); scanf("%[^\n]s", sent); while (sent [x] != '\0') { if (sent[x] >= 'a' && sent[x] <= 'z') { sent[x] = sent[x] & 0xDF; } x++; } printf("%s \n", sent); }
Translate the following C program into NASM. #include int main() { int x = 0; char sent[20]; printf("Enter sentence: "); scanf("%[^\n]s", sent); while (sent [x] != '\0') { if (sent[x] >= 'a' && sent[x] <= 'z') { sent[x] = sent[x] & 0xDF; } x++; } printf("%s \n", sent); }
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 6PE
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Question
Translate the following C program into NASM.
#include <stdio.h>
int main()
{
int x = 0;
char sent[20];
printf("Enter sentence: ");
scanf("%[^\n]s", sent);
while (sent [x] != '\0') {
if (sent[x] >= 'a' && sent[x] <= 'z') {
sent[x] = sent[x] & 0xDF;
}
x++;
}
printf("%s \n", sent);
}
Use indexing (the [ebx] form). You can use the following pseudocode in the “bss” to allocate the array:
slen equ 20
sent resb slen
Note: the scanf format string of “%[^\n]s” keeps reading characters until the newline (otherwise it would end at the first space).
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