Plzz complete the coding using c language and plz do not use any other library other than stdio . h
Plzz complete the coding using c language and plz do not use any other library other than stdio . h
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Plzz complete the coding using c language and plz do not use any other library other than stdio . h
Transcribed Image Text:Given two arrays, we can append one array to the end of the other. For example:
x1
1.1
2.3
4.2
x2
0.7
1.6
3.2
1.3
result
2.3
4.2
0.7
1.6
3.2
1.3
Write a program which reads two arrays x1 and x2 from the files array1.txt and array2.txt,
appends x2 to the end of x1, and then writes the result to the file appendarraysout.txt.
In more detail main carries out the following steps:
opens the three files array1.txt, array2.txt, and appendarraysout.txt.
. reads the first array x1 from the file array1.txt.
• reads the second array x2 from the file array2.txt.
calls the function append(), which appends x2 to the end of x1 resulting in a new array
y.
• writes the size of y followed by the values of y to the file appendarraysout.txt.
![#include<stdio.h>
float append(int n, int n2, float *ptr1, float *ptr2);
int main(void) {
int i=0, n=0;
float x1, x2;
FILE fin1 = fopen("array1.txt", "r");
FILE* fin2 = fopen("array2.txt", "r");
while() {
n1++;
}
while (){
n2++;
}
for (i=0;i<n; i++){
y[i]=x1[i];
}
for(i=0; i<n2; i++){
y[i]=x2[i];
}](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F88f9be6d-d8dd-4674-ab78-d1dd0cdba8bb%2F043c3346-5bb3-4873-a409-e0fdfa99650b%2Fz8zgx2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:#include<stdio.h>
float append(int n, int n2, float *ptr1, float *ptr2);
int main(void) {
int i=0, n=0;
float x1, x2;
FILE fin1 = fopen("array1.txt", "r");
FILE* fin2 = fopen("array2.txt", "r");
while() {
n1++;
}
while (){
n2++;
}
for (i=0;i<n; i++){
y[i]=x1[i];
}
for(i=0; i<n2; i++){
y[i]=x2[i];
}
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