### Problem DescriptionTom and Fred are carrying a uniform 2.0 m board (assume mass-less). Tom is supporting the board at the left end while Fred is on the right end as shown. Tom has attached his lunch to the board 0.6 m from Fred and the tension in the string is 200 N.**Objective:**Find the force that Fred exerts on the board.### Diagram Explanation- **Tom** is holding one end of the board.- **Fred** is holding the other end.- The board is 2 meters long.- A lunch box is hanging 0.6 meters from Fred's side.- The tension in the string is given as 200 N.### ChoicesA) 60 N B) 200 N C) 80 N D) 140 N E) 100 N Choose the correct option based on the physics of the scenario.### Solution ApproachTo solve this problem, consider the principles of equilibrium and torque:1. **Equilibrium**: The sum of all forces on the board must be zero.2. **Torque**: The board must also be in rotational equilibrium, meaning the sum of all torques about any point must be zero.Calculate the torques around Tom's side and balance the forces to find the force that Fred must exert.

Answered: Image /qna-images/answer/c10e724d-e1fd-487c-b67d-56cf4cad7add.jpg

Tom and Fred are carrying a uniform 2.0 m board (assume mass-less). Tom is supporting the board at the left end while Fred is on the right end as shown. Tom has attached his lunch to the board 0.6 m from Fred and the tension in the string is 200N.

Tom and Fred are carrying a uniform 2.0 m board (assume mass-less). Tom is supporting the board at the left end while Fred is on the right end as shown. Tom has attached his lunch to the board 0.6 m from Fred and the tension in the string is 200N.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A hungry bear weighing 85.0 kg walks out on a beam in an attempt to retrieve a basket of food hanging at the end of the beam. The beam is uniform, has a mass of 20.0 kg, is 8.00 m long, and pivoted at the wall; the basket weighs 10.0 kg. If the wire can withstand a maximum tension of 900 N, what is the maximum distance that the bear can walk before the wire breaks? ←x 60.0⁰ Goodies
A 4 m long horizontal uniform beam of mass 20 kg is supported by a wire as shown in the figure. The wire makes an angle of 23 degrees with the beam. Attached to the beam 1.2 m from the wall is a ball with a mass of 48 kg. What is the tension in the string? K 0 (m)
How do you do this? A hungry bear weighing 700 N walks out on a beam in an attempt to retrieve a basket of goodies hanging at the end of the beam (see figure below). The beam is uniform, weighs 200 N, and is 6.00 m long, and it is supported by a wire at an angle of ? = 60.0°. The basket weighs 80.0 N. a) When the bear is at x = 1.00 m, find the tension (in N) in the wire supporting the beam and the components of the force exerted by the wall on the left end of the beam. b) If the wire can withstand a maximum tension of 875 N, what is the maximum distance (in m) the bear can walk before the wire breaks?
A sign for a pizza restaurant hangs from a 2.60-m long rod extended out from a building. A cable, attached to the building, is attached to the rod at a point that is 2.10 m from the hidge. (See the figure.)The mass of the rod is 4.80 kg. The mass of the sign is 7.10 kg. The angle between the building and the rod is 50.0 degrees. The angle between the cable and the horizontal is 38.0 degrees. The tension in the cable is 90.27 N.What is the vertical component of the reaction force from then hinge on the rod?
A uniform beam with a length of 2.50 meters and a mass of 85.0 kg rests on two ropes. A person of mass 65.0 kg is standing on the far right end of the beam. The beam is not moving.Calculate the tension in the rope on the left, in Newtons (N).Calculate the tension in the rope on the right, in Newtons (N).
A beam resting on two pivots has a length of L = 6.00 m and mass M = 77.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distance ℓ = 4.00 m from the left end exerts a normal force n2. A woman of mass m = 61.5 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. (a) Use the force equation of equilibrium to find the value of n2 when the beam is about to tip. (b) Using the result of part (c) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.x = (c) Check the answer to part (e) by computing torques around the first pivot point.x = (d)Except for possible slight differences due to rounding, is the answer the same for F and E?
A 1.0 m long uniform iron bar is balanced on triangular support at its middle with 200 g hanging form it on a string tied 10 cm from the middle and mass m hanging form it on a string tied 40 cm from the middle of the bar. What is the mass m? cc (The triangular support and 200 g mass on a string and mass m on a string are the only things touching the bar.)
A beam resting on two pivots has a length of L = 6.00 m and mass M = 87.0 kg. The pivot under the left end exerts a normal force n₁ on the beam, and the second pivot placed a distance = 4.00 m from the left end exerts a normal force n₂. A woman of mass m = 52.0 kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip. -L- m M (a) Sketch a free-body diagram, labeling the gravitational and normal forces acting on the beam and placing the woman x meters to the right of the first pivot, which is the origin. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen (b) Where is the woman when the normal force n₁ is the greatest? x = L m (c) What is n, when the beam is about to tip? N (d) Use the force equation of equilibrium to find the value of n₂ when the beam is about to tip. N (e) Using the result of part (c) and the torque equilibrium equation, with torques computed…
A man holds a 195-N ball in his hand, with the forearm horizontal (see the figure). He can support the ball in this position because of the flexor muscle force M , which is applied perpendicular to the forearm. The forearm weighs 20.7 N and has a center of gravity as indicated. Find (a) the magnitude of M and the (b) magnitude and (c) direction (as a positive angle counterclockwise from horizontal) of the force applied by the upper arm bone to the forearm at the elbow joint. Upper arm bone- Flexor muscle M Elbow cg joint 0.0510 m+ 0.0890 m -0.330 m- (a) Number i Units (b) Number i Units (c) Number i Units >
A hiker, who weighs 659 N, is strolling through the woods and crosses a small horizontal bridge. The bridge is uniform, weighs 4280 N, and rests on two concrete supports, one on each end. He stops 1/5 of the way along the bridge. What is the magnitude of the force that a concrete support exerts on the bridge (a) at the near end and (b) at the far end?
To get up on the roof, a person (mass 87.0 kg) places a 5.60 m aluminum ladder (mass 14.0 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. The ladder rests against a plastic rain gutter, which we can assume to be frictionless. The center of mass of the ladder is 2 m from the bottom. The person is standing 3 m from the bottom. What are the magnitudes (in N) of the forces on the ladder at the top and bottom? top N bottom N
A 10 m long board has a mass of 7 kg. The left end of the board is against a wall and it sticks straight out like a boom. A rope is tied 1 m from the right end of the board and makes a 44 degree angle with the boom. A 25 kg box hangs 3 m from the right end. Find the tension in the rope.