Title: Pomacea canaliculata Meat as Natural Protein Diet for Broiler ChickenStatement of the Problem:Generally, this study aims to determine if P. canaliculata meat can be used as natural proteidiet for broiler chicken.Specifically, seek to answer the following questions:1. What are the weights of chicken after 45 days of feeding?2. Is there a significant difference in the weight of chicken feed with commercial pellets and P.canaliculata meat?Collected data on the weight of chicken after 45 days of feeding based on body weight ratiowith 9 chicken per treatment: Commercial pellets - 1.00, 0.99, 1.06, 1.67, 0.99, 1.04, 1.50, 1.23,and 1.59 in kgs; P. canaliculata meat - 1.69, 1.97, 2.00, 2.02, 1.96, 2.04, 1.78, 1.84, and 1.94 inkgs.Group StatisticsTreatmentNMeanStd. DeviationStd. Error MeanCommercial pellets91.230028045.09348WeightP. canaliculata meat91.9156.11938.03979Figure 2. Scientific study with 2 groups comparedGuide Questions:1. How will you present the data in tabular and textual forms to answering researchquestion 1?

Given Information: Consider the descriptive statistics table of the weight of chicken after 45 days…

Answered: Title: Pomacea canaliculata Meat as…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Solid fats are more likely to raise blood cholesterol levels than liquid fats. Suppose a nutritionist analyzed the percentage of saturated fat for a sample of 6 brands of stick margarine (solid fat) and for a sample of 6 brands of liquid margarine and obtained the following results: Stick:[26.4,25.5,25.8,26.1,25.6,26.3] Liquid:[16.9,16.9,17.2,17.3,16.3,17.1] We want to determine if there a significant difference in the average amount of saturated fat in solid and liquid fats. What is the test statistic? a) t = 42.744 b) z = 42.244 c) t = 42.244 d) z = 42.744 e) t = 25.816
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1. Birds can regrow feathers if they are lost. A researcher was interested in whether newly regrown feathers in the tails of northern flickers differed in colour (yellowness in particular) compared to older feathers. To test this, they measured the yellowness of one new and one randomly selected old feather on each of 20 birds. A plot of their data and the results of their analysis are shown below. Yellowness 160 150 140 130 new X Feather old Welch Two Sample t-test = data: Yellowness by Feather t = 1.5832, df 37.986, p-value 165 sample estimates: mean in group new mean in group old 147.9623 143.3000 160 New 155 150 145 140 135 = 0.1217 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -1.299296 10.623962 T T T T T 130 135 140 145 150 155 160 Old a) From the results above, what is the null hypothesis and what statistical conclusion do you make concerning it?
A survey collects demographic, socioeconomic, dietary, and health-related information on an annual basis. Here is a sample of 20 observations on HDL cholesterol level (mg/dl) obtained from the survey (HDL is "good" cholesterol; the higher its value, the lower the risk for heart disease). 36 48 51 55 66 50 52 46 85 35 45 34 40 44 40 62 94 36 31 47 (a) Calculate a point estimate (in mg/dl) of the population mean HDL cholesterol level. mg/dl (b) Making no assumptions about the shape of the population distribution, calculate a point estimate (in mg/dl) of the value that separates the largest 50% of HDL levels from the smallest 50%. mg/dl (c) Calculate a point estimate (in mg/dl) of the population standard deviation. (Round your answer to three decimal places.) mg/dl
A survey collects demographic, socioeconomic, dietary, and health-related information on an annual basis. Here is a sample of 20 observations on HDL cholesterol level (mg/dl) obtained from the survey (HDL is "good" cholesterol; the higher its value, the lower the risk for heart disease). 34 46 40 48 53 53 64 52 52 87 37 45 32 38 44 62 94 36 31 47 (a) Calculate a point estimate (in mg/dl) of the population mean HDL cholesterol level. mg/dl (b) Making no assumptions about the shape of the population distribution, calculate a point estimate (in mg/dl) of the value that separates the largest 50% of HDL levels from the smallest 50%. mg/dl (c) Calculate a point estimate (in mg/dl) of the population standard deviation. (Round your answer to three decimal places.) mg/dl (d) An HDL level of at least 60 is considered desirable as it corresponds to a significantly lower risk of heart disease. Making no assumptions about the shape of the population distribution, estimate the proportion p of the…
During a particularly dry growing season in a southern state, farmers noticed that there is a delicate balance between the number of seeds that are planted per square foot and the yield of the crop in pounds per square foot. The yields were the smallest when the number of seeds per square foot was either very small or very large. The data in the table show various numbers of seeds planted per square foot and yields (in pounds per square foot) for a sample of fields. A 2-column table with 15 rows. Column 1 is labeled number of seeds (per square foot) with entries 28, 75, 30, 43, 71, 35, 40, 59, 66, 79, 85, 81, 16, 33, 16. Column 2 is labeled yield (pounds per square foot) with entries 131, 171, 132, 166, 169, 150, 161, 183, 173, 161, 147, 157, 86, 145, 86. Which scatterplot represents the seed and yield data? A graph titled number of Seeds and Crop Yield has seeds (per square foot) on the x-axis, and yard (pounds per square foot) on the y-axis. The points curve up to a point, and…
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1. Parking at a large university can be extremely difficult at times. One particular university is trying to determine the location of a new parking garage. As part of their research, officials are interested in estimating the average parking time of students from within the various colleges on campus. What's the target parameter of interest?
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